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anonymous
 5 years ago
Solve for k: ((162k)/3)^2+(2((162k)/3))+k=40
anonymous
 5 years ago
Solve for k: ((162k)/3)^2+(2((162k)/3))+k=40

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(25664k+4k^2)/9 + (324k)/3 + k =40

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then put them all over 9

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(25664k+4k^2 + 9612k+9k360)/9 = 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Wait how'd you get the first step?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Never mind 16 squared?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I expanded the first part squared and multiplied the second part by 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do you know what to do from there?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just say so if you need more help

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay i got to 64k+4k^212k+9k=352, how do i get all the k's alone?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can group all the ks together and get 4k^2 + 67k +352 = 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then use the quadratic equation with a=4, b=67, c=352

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0whats the quadratic equation?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[k=(b \pm \sqrt{b ^{2}4ac})/2a\]
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