Find the quadratic equation from the following data The intercepts are (-3,0) and (0,18)

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

Find the quadratic equation from the following data The intercepts are (-3,0) and (0,18)

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

quadratic has the form f(x)=ax^2+bx+c right?
we are given that those two points lie on the quatric so we have f(-3)=a(-3)^2+b(-3)-c=0 and we have f(0)=c=18 so f(-3)=9a-3b-18=0
so we have 9a-3b=18 or 3a-b=6 if we divide both sides by 3

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

but we have two unknowns so now i'm stuck maybe we should try the form f(x)=a(x-h)^2+k
I don't know much, but if I am correct, the equation must be of the form ay^2+by+c=0
As you see there is only one x intercept
you can use either form
I don't think so, as you see while you use the x form, you are putting the value of x in the equation, and that I think will not work
Though I am not sure
we know the y-intercept which is (0,18) so we have f(x)=a(x-h)^2+18 now we need to find h and a
0=f(-3)=a(0-h)^2+18=ah^2+18 so we have ah^2=-18
so either way we still have two unknowns
oh i see what you are saying no y=f(x) not x=y
Now you got it
its f(x)=ax^2+bx+c or you can use f(x)=a(x-h)^2+k
we don't know anything else about the parabola?
I beg your pardon?
If you find any solution please post it here, I will have to leave now, as there is a black out here
i was just asking if we know anything else about the parabola?
go lokisan!
Iam, I may be able to look at it a bit later. My first impressions of it are to find the slope of the line that joins the two points, use that to perform a rotation back to the x-axis, solve the equation normally and then transform back. Or you could transform the general equation by the same angle and solve straight from the points. Like I said, this is a cursory glance. I don't have time available at the moment to work through it properly, but I will when I can...promise.
haha, just saw what you wrote, myininaya...
lol .
And I forgot to say, you may want to translate your points to the right 3 units before rotating...so your points would be (-3,0) --> (0,0) and (0,18) --> (3,18). Hope this is making sense.
ignorant, do we know anything else about the parabola?
like the vertex or something else?
No that is all the information I have about it
can you make sense out what lokisan is saying? it looks like he has a way to find the equation of the parabola
Yes, I can get the idea of what he is saying. And I am trying to work it out on pen and paper. If you have any more clue, please post it
do you know derivatives?
Yes sure
http://en.wikipedia.org/wiki/Rotation_matrix
ok awesome
f'(x)=2ax+b
Forget the matrix stuff if you haven't done it. You can use the equations.
Actually I happen to have learnt that rotation part of matrix
Good
Your problem is: (3,18)=R(x,y) where the ( , ) are vectors and R is the rotation matrix. You need to invert R to find (x,y)=R^{-1}(3,18). You'll then have two points, (0,0) and (x,0) (since both points will now be on the x-axis). I'm rushing through this...I've just thought of a 'better' method, but I'm rushed...if I can sort it out later, I will.

Not the answer you are looking for?

Search for more explanations.

Ask your own question