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anonymous
 5 years ago
Find f'(x), f(x) = ((3x  5) / (2x + 1))^3
anonymous
 5 years ago
Find f'(x), f(x) = ((3x  5) / (2x + 1))^3

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for h(x) = f(x)/g(x) use the quotient rule [f'(x)g(x)  g'(x)f(x)]/g'(x)^2. Use the chain rule to evaluate g(x).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I get up here: \[3{{(3x  5) \cdot 2  (2x + 1) \cdot 3} \over (2x + 1)^2}^2\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ah sorry misread your function.... :/

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ahh, in the denominator is g'(x)^2 ? that's one of my mistakes

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is a really good tutorial: http://tutorial.math.lamar.edu/Classes/CalcI/ProductQuotientRule.aspx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what's the answer? (13 / (2x + 1))^3 ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0or, 3(13 / (2x + 1))^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well I haven't solved it all the way through, but I would simply it to \[(3x5)^{3}/(2x+1)^{3}\] then use the chain rule to find the derivatives of the numerator and denominator, then use the quotient rule to find the final answer.
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