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anonymous

  • 5 years ago

Find f'(x), f(x) = ((3x - 5) / (2x + 1))^3

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  1. anonymous
    • 5 years ago
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    for h(x) = f(x)/g(x) use the quotient rule [f'(x)g(x) - g'(x)f(x)]/g'(x)^2. Use the chain rule to evaluate g(x).

  2. anonymous
    • 5 years ago
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    I get up here: \[3{{(3x - 5) \cdot 2 - (2x + 1) \cdot 3} \over (2x + 1)^2}^2\]

  3. anonymous
    • 5 years ago
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    ah sorry misread your function.... :/

  4. anonymous
    • 5 years ago
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    ahh, in the denominator is g'(x)^2 ? that's one of my mistakes

  5. anonymous
    • 5 years ago
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    this is a really good tutorial: http://tutorial.math.lamar.edu/Classes/CalcI/ProductQuotientRule.aspx

  6. anonymous
    • 5 years ago
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    ok.

  7. anonymous
    • 5 years ago
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    what's the answer? (-13 / (2x + 1))^3 ?

  8. anonymous
    • 5 years ago
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    or, 3(-13 / (2x + 1))^2

  9. anonymous
    • 5 years ago
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    well I haven't solved it all the way through, but I would simply it to \[(3x-5)^{3}/(2x+1)^{3}\] then use the chain rule to find the derivatives of the numerator and denominator, then use the quotient rule to find the final answer.

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