## anonymous 5 years ago Infinite series e^(-n)sin(n) ? what test should I use?

1. anonymous

Ok. Lets do this. e^(-n) can be rewritten as 1/e^n. So when we combine this with our sin(n) we get $\sin (n)/e^n$

2. anonymous

I think you will need to use the Ratio Test.

3. anonymous

Looks like a transient term, the series will converge. e^-n will be a very small number Integral test will conclude that it is a converging series.