Find the vertices, foci, and asymptotes of the hyperbola. x^2 − 7y^2 = 8 can any one help me with this?

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Find the vertices, foci, and asymptotes of the hyperbola. x^2 − 7y^2 = 8 can any one help me with this?

Mathematics
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does this help? you can write the equation as (x-0)^2/8-(y-0)^2/(8/7)=1
yes iv got all that. im just having trouble finding the asymptotes.
http://www.algebra.com/algebra/homework/Quadratic-relations-and-conic-sections/change-this-name17360.lesson

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Other answers:

it says do sqrt(8)/sqrt(8/7) is the slope of the asymptote
=sqrt(7)
yes ive done that but i get a weird radical that i dont know how to reduce?...
what is it?
sqrt 65/7 / 2 sqrt 2
sqrt(65/7)/[2sqrt(2)]?
yes
thats not the slope is it? what is that?
the asymptotes
I don't know about that. i have to go though. i'm sorry. if you want to simplify the above that you wrote, it is sqrt(65)/[2*sqrt(2)]
thanks.
sqrt(65)/[2*sqrt(2)]???
oops lol
sorry it was suppose to be 1/2 * sqrt(65/14)
ok let me try it.
you have double fraction so you change to multiplication by flipping the second fraction
1/2 * sqrt(65/14) is the final answer right?

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