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anonymous
 5 years ago
Sketch a triangle that has acute angle θ, and find the other five trigonometric ratios of θ.
Tan(degree sign)= sqr of 15
anonymous
 5 years ago
Sketch a triangle that has acute angle θ, and find the other five trigonometric ratios of θ. Tan(degree sign)= sqr of 15

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sin(θ) = cos(θ) = csc(θ) = sec(θ) = cot(θ) =

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'll take a shot at it..... So tan is sin/cos which is y/x So x = 1 and y = sqrt15 Then do x^2 + y^2 = r^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Does that seem right so far?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I have no idea. I'm been trying to figure this out for a while now. Thanks for trying! If it is right kudos to you :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So x^2 + y^2 = r^2 (r is the hypotenuse) (1)^2 + (sqrt15)^2 = r^2 1+ 15=r^2 16=r^2 sqrt16=r r=4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So now you have all the needed numbers to finish the problem. x = 1 y = sqrt15 r = 4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sin = sqrt15/4 cos = 1/4 tan = sqrt15 csc = 4/sqrt15 sec = 4 cot = 1/sqrt15

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thank you so much! But the Sin= sqrt15/4 is not the right answer.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I can't seem to figure that one out.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Is everything else right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Is it (sqrt15)/4 or is the 4 inside the sqrt of 15?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It is (sqrt15)/4 because it is y/r.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, yeah that's the right answer. Thanks again :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah. But I have another problem. Use the figure and the value given below to answer the following questions. Assume A = 4. (a) Express x in terms of trigonometric ratios of θ. (b) Express y in terms of trigonometric ratios of θ.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0ok...gonna need the picture tho :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0or use this to let me know what I am looking at :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0A is the Adjacent angle, y is the hypotenuse, and x is the opposite. Acute triangle.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0LIKE THIS? opps caps were on lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The A is on the bottom, but everything else is in the right place.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0are we dealing with a right triangle?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0A is bottom left angle?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Just the bottom angle. I'll try to put up the pic

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0ahhh...thats better, when you said A was the adjacent angle it threw me :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0x is equal to "sin(t)" sin(t) = x/y x = y * sin(t)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0probably want my to use A for that eh....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0A = 4...that helps....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't understand how to use it in the equation.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0I think its asking for all the trig functions that use the "x" there and how we would solve for "x": x = yadayadayada stuff like that, might be overkill, but better safe than sorry :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0sin(t) = x/y ; x = y * sin(t) csc(t) = y/x ; x = y/csc(t) tan(t) = x/4 ; x = 4tan(t) cot(t) = 4/x ; x = 4/cot(t) thats all of them thatll use the x....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0you know how the trig functions are defined?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What do I do for this problem though? \

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the names that are given to them arent all that important, but since they got em, might as well use em. sin is simply the ration of the opposite side from the angle divided by the hypotenuse: usually abbreviated as opp/hyp.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0you just express x or y in terms of the trig functions... as far as I can tell

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0...simply the *ratio* of the .....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0oonce you know sin and cos, the rest are just made with these two...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How would I find x and y then?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0you would need more information to actually solve for x and y; you would need to know the measurement of an angle, or another side so that you could work things out. But what you have is not enough information to get any "solid" answers for the rest of it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That's all it shows in the problem.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no angle or anything.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0then it cant expect you to "solve" for any values, just want you to be able to express what x and y are in terms of the rest of the information

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Here is another similar one if you can help with this one. Find the side labeled x. Assume a = 4.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How would I express them in terms then?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0this we have enough information to solve :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0well, I wrote up all the ones I could think of for the x values up there.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0if a = 4 then sin(60) = x/4 sin(60) is one of those basic angles you learn in trig class and are expected to memorize. the sin(60) = sqrt(3)/2 sqrt(3) x  =  2 4 2sqrt(3) = x is as far as you can go without a calculator

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh.. ok I get this one. But the other has me confused :P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It just says "Express x in terms of trigonometric ratios of θ."

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the other one just says: (a) Express x in terms of trigonometric ratios of θ. (b) Express y in terms of trigonometric ratios of θ. it doesnt say "solve" for any particular value. Just use what you know about the trig functions to be able to express x or y in terms of them

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0like this: sin(t) = x/y ; x = y * sin(t) csc(t) = y/x ; x = y/csc(t) tan(t) = x/4 ; x = 4tan(t) cot(t) = 4/x ; x = 4/cot(t)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How would I go about doing that? I tried the X ones you put up, but they don't seem to work.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0do you have anymore options :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0then I would just skip it and move to the next question..... :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lifes to short to worry about 1 trig problem that they dont give you enough information about right ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Haha... Thanks so much for your help. I'm actually learning math more from you than my stupid professor lol :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lol .... well, I do have the time.....alot of time :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Are you in college or what?
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