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anonymous

  • 5 years ago

you invest a total of $13750 in two companies (part in SLW and part in STDY). After one year the SLW investment increases by 6.4% and the STDY investment increases by 3.9%. How much was invested in STDY if the TOTAL increase in the initial investment was 6.2%

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  1. amistre64
    • 5 years ago
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    so if the total increase of the initial investment (from both companies? or just from this one) is 6.2%; then ....

  2. anonymous
    • 5 years ago
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    so 6.2 =....

  3. anonymous
    • 5 years ago
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    am i right so far?

  4. amistre64
    • 5 years ago
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    x + y = 13750 x(6.4%) + y(3.9%) = 13750(6.2%) we good with this so far?

  5. anonymous
    • 5 years ago
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    yea and i can take it from there

  6. anonymous
    • 5 years ago
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    i can just use the elimination method right?

  7. amistre64
    • 5 years ago
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    id rename it SLW and STDY just to be on the safe side :)

  8. amistre64
    • 5 years ago
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    elimination is when you canel out one variable...it might be an option; but usually I just solve for one of the top variables and sustitute it into the bottom one.

  9. anonymous
    • 5 years ago
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    that would be easier :)

  10. amistre64
    • 5 years ago
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    x + y = 13750 y = 13750 - x --------------------------- x(.064) + y(.039) = 13750(.062) x(.064) + (13750 - x)(.039) = 13750(.062)

  11. amistre64
    • 5 years ago
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    solve for "x" and then back it up for "y"

  12. anonymous
    • 5 years ago
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    right. i will tell you what i get, one minute

  13. anonymous
    • 5 years ago
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    i got 1.59 for x now about to plug back in for y

  14. anonymous
    • 5 years ago
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    i think i did something wrong thats REALLY small

  15. amistre64
    • 5 years ago
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    ok....ill double check your work :)

  16. anonymous
    • 5 years ago
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    im lost

  17. amistre64
    • 5 years ago
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    x = 12650

  18. anonymous
    • 5 years ago
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    i multiplied everything

  19. anonymous
    • 5 years ago
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    and got .064x + 536.25x = 852.5

  20. anonymous
    • 5 years ago
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    solved for x and got 1.59 (rounded) but that doesnt work when i solve for y

  21. amistre64
    • 5 years ago
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    x(.064) + (13750 - x)(.039) = 13750(.062) .064x -.039x + 536.25 = 852.50 .025x = 316.25 x = 316.25/.025 x = 12650

  22. anonymous
    • 5 years ago
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    OHH i didn't distribute the .039 properly

  23. anonymous
    • 5 years ago
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    can you just clarify for me and show me kinda step by step how you set up the two equations? based off of the word problem?

  24. amistre64
    • 5 years ago
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    I can..if your still around

  25. anonymous
    • 5 years ago
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    yes

  26. amistre64
    • 5 years ago
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    There are 2 companies that you invest a certain number of dollars in: one company get s "x" amount of dollars and the other gets "y" amount of dollars. the amount invested into both companies has to equal 13750. x + y = 13750

  27. anonymous
    • 5 years ago
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    right

  28. amistre64
    • 5 years ago
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    We know that each company has a different interest rate that they pay so we set this up accordingly we know that x amount of dollars gets us 6.4% and y amount of dollars gets us 3.9%. We are also told that the total amount of interest earned from all the monies invested was 6.2%.

  29. amistre64
    • 5 years ago
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    interest earned is a simple calcultion; it is amount of money times interest rate. plain and simple. x(6.4%) + y(3.9%) = 13750(6.2%) right?

  30. anonymous
    • 5 years ago
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    yes, ok i get it i just wanted to reinforce it

  31. amistre64
    • 5 years ago
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    ok :)

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