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I think i need to find the time each has traveled....?

to then determine the distance...since i already have the rate at which each was traveling

just not sure how to do that

sandy's time is 1 less than randys time

randy is an hour ahead and has cut off 90 km of his distance

right

so sandy can be represented as t-1

so start them heading towards each other at a distanceof 500-90

ok they are heading towards each other at a distance of 410

yay!! how much time do they travel combined in 1 hour?

195

195 km right...good
now how many hours is that till they are almost together?

410/195

after 2 hours how much distance is left?

2.1 to be exact

20 km

at a combined spped of 195km per hour, how long does it take them to cover 20 km?

195/20

other way around?

.10

and 1/10 of an hour is..... 6 minutes right?

correct

lets make sure this last bit is right....let me go over it...

wait, if it takes them both 2.1 hours to travel the distance

so add an hour to that and use it to calclate randys distance

nevermind i think thats wrong

they meet up at the same point :) when they meet, the distance is traveled

if 410 km is traveled combined in 2.1 hours

do I then make an equation of 2.1= t + (t-1)

90t =-105t right? maybe not...but it looks good

im confused now

195t - 410 = 0 is what we want I think

i feel like im making this more complicated than it is

at 195 km/hour and at "t" hours they cover 410 miles, so the distance is 0
195t-410 = 0

t = 410/195

but thats t for both of them

Randy has traveled for an extra hour so
90(t+1) = distance traveled by randy

wow i feel stupid

haha

lol :)

you really are superhero lol

279.23 km ;)
I wanted was hoping for a cool title like "turkey club on rye" but nooooooo.....

i got the answer. HAHAHA