anonymous
  • anonymous
FInd the indefinite integral using substitution. let u = 2x^2 + 3x + 9. (4x + 3)/ (2x^2 + 3x + 9)^(7/3)dx. can someone please give me the steps and answer . im in desperate need
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
du = (7/3)*(4x+3)^(4/3)
anonymous
  • anonymous
Do you see that?
anonymous
  • anonymous
Actually I take that back. Try [(7/3)(2x^2+3x+9)^(4/3)] * (4x+3) dx

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anonymous
  • anonymous
= du
anonymous
  • anonymous
I got (-3/4)[(2x^2)+3x+9)^(-3/4)]+C
anonymous
  • anonymous
Oh wait sorry. It's gettin close to bed time lol. Just ignore me. good grief
anonymous
  • anonymous
you just have to take the derivative of 2x^2+3x+9 and you get du=4x+3 dx...then you can substitute for the numberator of the integrand...then you can take the integral and back substitute u=2x^2+3x+9 after that.
anonymous
  • anonymous
numerator*
anonymous
  • anonymous
\[\int\limits_{?}^{?}( u^(-7/3) du\]
anonymous
  • anonymous
you can then take the integral of that
anonymous
  • anonymous
and then back substitute u to get the answer

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