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anonymous

  • 5 years ago

Factor 5x^3 + 10x^2 + 15x

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  1. dumbcow
    • 5 years ago
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    This is prime. It cannot be factored. If you graph this you will see the graph never crosses the x-axis. to see this you might try using quadratic formula

  2. anonymous
    • 5 years ago
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    youre an idiot, you can factor out x

  3. anonymous
    • 5 years ago
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    5x( x^2 + 2x + 3)

  4. dumbcow
    • 5 years ago
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    haha very true. sorry i was looking at factoring the remaining part after the x had been factored out

  5. anonymous
    • 5 years ago
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    ok , :)

  6. anonymous
    • 5 years ago
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    are you good at surface area integral? 2pi y dS

  7. dumbcow
    • 5 years ago
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    somewhat i haven't used that too much

  8. anonymous
    • 5 years ago
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    hmmm, i have a question posted on the left . its about a torus

  9. anonymous
    • 5 years ago
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    Surface area of a torus which has radius r which is generated by the circle centered at (R,0) with radius r. And assume R>r. So the equation of the circle is (x-R)^2 +y^2 = r^2. FOr some reason my integral does not work. i have integral 2pi y dS, where y = sqrt [r^2 - (x-R)^2], and ds = sqrt ( 1 + dy/dx ^2). dy/dx = -2(x-R)/ (2sqrt(r^2 - (x-R)^2)). anyways, integration limits , the lower limit is R-r, and upper R+r

  10. dumbcow
    • 5 years ago
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    ok ill take a look

  11. anonymous
    • 5 years ago
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    s

  12. anonymous
    • 5 years ago
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    the answer i should get is 4pi^2 r*R

  13. anonymous
    • 5 years ago
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    my integral is int sqrt [r^2 - (x-R)^2] sqrt [ 1 + [2(x-R)/ (2sqrt(r^2 - (x-R)^2))]^2 .

  14. dumbcow
    • 5 years ago
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    the setup looks correct as do the functions

  15. dumbcow
    • 5 years ago
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    it prob is a computational error, thats a pretty big integral.

  16. anonymous
    • 5 years ago
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    yes it is

  17. dumbcow
    • 5 years ago
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    is that last part sqrt[] all squared so it cancels out

  18. dumbcow
    • 5 years ago
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    hmm nevermind i thought i could reduce it for you. as far as the integration you'll have to find someone else to help you or use some graphing software. sorry

  19. anonymous
    • 5 years ago
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    we can reduce it

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