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anonymous
 5 years ago
powerseries Lifesaver (1 fan)Become a fan You're a fanNot a fan
Surface area of a torus which has radius r which is generated by the circle centered at (R,0) with radius r. And assume R>r. So the equation of the circle is (xR)^2 +y^2 = r^2. FOr some reason my integral does not work. i have integral 2pi y dS, where y = sqrt [r^2  (xR)^2], and ds = sqrt ( 1 + dy/dx ^2).
dy/dx = 2(xR)/ (2sqrt(r^2  (xR)^2)).
anyways, integration limits , the lower limit is Rr, and upper R+r
anonymous
 5 years ago
powerseries Lifesaver (1 fan)Become a fan You're a fanNot a fan Surface area of a torus which has radius r which is generated by the circle centered at (R,0) with radius r. And assume R>r. So the equation of the circle is (xR)^2 +y^2 = r^2. FOr some reason my integral does not work. i have integral 2pi y dS, where y = sqrt [r^2  (xR)^2], and ds = sqrt ( 1 + dy/dx ^2). dy/dx = 2(xR)/ (2sqrt(r^2  (xR)^2)). anyways, integration limits , the lower limit is Rr, and upper R+r

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