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anonymous
 5 years ago
How do I use the exponential shift to solve the linear differential equation y'' + 7y' +12y = 2(e^3)(cos2x)
anonymous
 5 years ago
How do I use the exponential shift to solve the linear differential equation y'' + 7y' +12y = 2(e^3)(cos2x)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im looking to find the general solution y = yc +yp. so far i have solved the homogenous part of the equation yc. yc = Ae^3x + Be^4x. i cant solve for yp yet.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Let me do it on paper first. I think it would be murder typing it out.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0haha thank you! any help will go a long way

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i'll continue to try draw something out of my mess of numbers and letters while i wait

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i also figured that the derivative operator 'D' helps so that the LHS = (D^2 + 7D +12)y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You do mean e^{3x}, don't you?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0When I get to factors that need expanding, I'm going to get Mathematica to do that (save time).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok no worries. if i dont follow il just let u know

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So what happened, your lecturer just dump theory on you with no demonstration?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0he demonstated with the d.e. y'' + 6y' + 13y = x(e^3x)(sin2x) however that takes y = imaginary(Y) and also takes into account the complex numbers. As my roots are reall 3, 4 and i take y=real(Y) instead, i dont know what yp to try

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0he pretty much chalk vomits all over the board without going into the specifics of how he gets to places

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Not trained to teach...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its really quite frustrating... luckily we are changing lecturers next week.. sorry for any hassle im causing you!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just give me a fan point and i'll be happy

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wow thanks! im just gona go through it and check i understand.. haha ok sure how do i do that?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just click my 'become a fan' link...if there isn't one there, refresh the page...should work then

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ps. is there a place to download mathmatica for free? ok right on it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0www.wolframalpha.com The guy who made mathematica made this site. It can do a lot of things like integration, solving differential equations, plotting, etc.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0fanned. thanks a million! will i still be able to ask help from you if i have any more troubles..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is wolfram's solution to your equation http://www.wolframalpha.com/input/?i=y%27%272y%27%2B5y+%3D+16x^3*e^%283x%29+++

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0woops...no it's not...wait.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0haha! i was like crap.. i did notttttt get that

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0http://www.wolframalpha.com/input/?i=y%27%27%2B7y%27%2B12y+%3D+2e^%283%29cos%282x%29

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0haha ur awesome at pen to paper but im afraid you did the same typo as me last time. theres an 'x' in e^3x. however the graphs dont look how i thought they would..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0graphs in the correct version*

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yep :) i thought it would have more of a decaying oscillation as it is overdamped.. is it because of the negative exponential? why?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So, am I right in understanding you've finished deriving the solution?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0And you're reading off that and not Wolfram?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry no. i was comparing my notes to the graphs of wolfram.. but! i havent read through the wolfram content yet.. just making observations. if you would like you can continue helping other students.. and im guessing when i need help again it will notify you?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes, I get an email if you respond to a thread I've been in. Are you fine to derive the rest?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If an error's been made on my part, it's because it's after 1am where I am. If you need help in the next ~1224hrs, I may not be around. You'd should try your luck with someone else.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i should be ok for now thanks :) it takes me quite a while longer than you to come up with a solution

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yep me too. 1:22am. ok do u recommend anyone else?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't know the particular skill level of people on here. You may have to post and cross fingers.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Is this an assignment due tomorrow or something?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ahah yeh you caught me out. due 2pm. i wish i could say im a more dedicated student working til the early hours of the morning doing maths... ah the thrills of life!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well, since your timezone's mine, if I see something from you in the morning and I can respond, I will. My day will be hell busy, though.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Anyways, good luck. I seriously have to hit the sack.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thanks you are a hero! night!
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