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anonymous

  • 5 years ago

A trigonometric question: On an ABC triangle , the edges are a, b and c. (b-c)/(b+c)=1/(root3) m(A)=60 degree angle what is angle of m(B) ?

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  1. amistre64
    • 5 years ago
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    if its a right triangle, then the m(B) will equal 30 degrees. if its not a right triangle, then a picture would be helpful

  2. anonymous
    • 5 years ago
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    There is no given shape.Thanks anyway.

  3. anonymous
    • 5 years ago
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    Answer is equal 105 degrees.

  4. amistre64
    • 5 years ago
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    then you could do it the hard way by making a system of equations: b - c = 1 b + c = sqrt(3) and finding your b and c....

  5. amistre64
    • 5 years ago
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    then use the law of cosines to find "a" and the law of sines to find all your angles

  6. amistre64
    • 5 years ago
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    b = 1+c (1+c) +c = sqrt(3) 1 + 2c = sqrt(3) 2c = sqrt(3)-1 c = (sqrt(3)-1)/2; b = (1 + sqrt(3))/2

  7. anonymous
    • 5 years ago
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    I found a=6 then I found , 12/sqrt(3)=(sqrt(3)-1)/sin(B) But couldn't go further

  8. amistre64
    • 5 years ago
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    if your a=6 is good; then: sinA sinB) ---- = ----- a b sinB = b sin(A)/a

  9. amistre64
    • 5 years ago
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    sinB = [ (1 + sqrt(3))/2 ] [sqrt(3)/2] / 6 sinB = (sqrt(3) +3)/24

  10. amistre64
    • 5 years ago
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    sinB = sqrt(3)/24 + 1/8

  11. amistre64
    • 5 years ago
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    the sin inverse funtion will give you one angle for that taio; but you have to be aware that 2 angles are possible with a positive sin.

  12. amistre64
    • 5 years ago
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    taio means ratio..... somehow :)

  13. anonymous
    • 5 years ago
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    Prof ,My problem is how can i turn this to degree. :)

  14. amistre64
    • 5 years ago
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    with the sin inverse function on a calculator.

  15. anonymous
    • 5 years ago
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    I got it , sin inverse function , i will try thanks :)

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