## anonymous 5 years ago how do i get my quadratic answer in decimal form

1. amistre64

divide......

2. amistre64

or do you mean that sqrt part?

3. anonymous

$33\pm \sqrt{65}\over 32$

4. amistre64

split it up int0 its parts: 33/32 + sqrt(65)/32 33/32 - sqrt(65)/32 .969 ----------- 33 | 32.00000 - 297 ---- 230 - 198 ---- 320 - 297 ----- 230 <- this is repeating so we use this symbol -- .96 that is .96 with a bar above it to indicate that it is a repeating decimal

5. amistre64

the trick to doing the sqrt part is really to know that x^2 + 2xy + y^2 is the key to your results. We we seperate the number up into groups of 2 starting at the decimal and going in both directions, for example: 12345.654 becomes 1 23 45. 65 40 00 00 00

6. amistre64

your sqert(65) is already in a group of "2" so we have: ------------------ \/65. 00 00 00 00 00

7. amistre64

now we need to find a number for "x^2" that is close to but less than the first grouping; in this case close to but less than 65. 8^2 = 64; so lets use that: 8. ------------------ \/65. 00 00 00 00 00 -64 -------- 1 00 we have our "x^2, now we need to "2x" and find "y" to add to this. 8. ------------------ \/65. 00 00 00 00 00 -64 -------- 2x+y| 1 00 16 __ | 0 is the only thing we can use for y because 160 is greater than 100 and we cant use anything else.

8. amistre64

8. 0 y ------------------ \/65. 00 00 00 00 00 -64 -------- 160 | 1 00 ------- 160+ y | 1 00 00 and continue

9. anonymous

sweet, thanks!

10. amistre64

its either that or use a calculator :)