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anonymous
 5 years ago
how do i get my quadratic answer in decimal form
anonymous
 5 years ago
how do i get my quadratic answer in decimal form

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0or do you mean that sqrt part?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[33\pm \sqrt{65}\over 32\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0split it up int0 its parts: 33/32 + sqrt(65)/32 33/32  sqrt(65)/32 .969  33  32.00000  297  230  198  320  297  230 < this is repeating so we use this symbol  .96 that is .96 with a bar above it to indicate that it is a repeating decimal

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the trick to doing the sqrt part is really to know that x^2 + 2xy + y^2 is the key to your results. We we seperate the number up into groups of 2 starting at the decimal and going in both directions, for example: 12345.654 becomes 1 23 45. 65 40 00 00 00

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0your sqert(65) is already in a group of "2" so we have:  \/65. 00 00 00 00 00

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0now we need to find a number for "x^2" that is close to but less than the first grouping; in this case close to but less than 65. 8^2 = 64; so lets use that: 8.  \/65. 00 00 00 00 00 64  1 00 we have our "x^2, now we need to "2x" and find "y" to add to this. 8.  \/65. 00 00 00 00 00 64  2x+y 1 00 16 __  0 is the only thing we can use for y because 160 is greater than 100 and we cant use anything else.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.08. 0 y  \/65. 00 00 00 00 00 64  160  1 00  160+ y  1 00 00 and continue

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0its either that or use a calculator :)
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