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anonymous
 5 years ago
what is the d'(y)= (y^2)^2+(y3)^2?? any help?
anonymous
 5 years ago
what is the d'(y)= (y^2)^2+(y3)^2?? any help?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Are you asking for the first derivative with respect to y? If so, then you can do this many ways, the easiest is to simplify first. y^2^2=y^4, (y3)^2 = y^26y+9. Now just take the derivative of y^4+y^26y+9 with respect to y. This becomes 4y^3+2y6

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how would i find what y is worth from that equation .. because thats what i had before and i dont know where im going wrong?>

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What do you mean find out what y is worth? Y is a variable, it does not have a set value.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0critical points i meant of the derivative

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If you want critical points of the original function, then set the derivative equal to zero.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ya i know this ... but i cant find the right answer to it .. how would you do that when you have a third root of somthing ...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Take factors of the first term and then take factors of the second term. After that, you have to do some sythetic division.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry not second term i meant last term
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