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anonymous
 5 years ago
what are the critical points of 4y^3+2y6? cant figure it out .. tried a lot of things. .
anonymous
 5 years ago
what are the critical points of 4y^3+2y6? cant figure it out .. tried a lot of things. .

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how did you get that >?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i looked at your probelm and then decided to ask you if 4y^3 was what you meanrt to type....then waited for you to answer :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0if there are no typos in your problem than I would begin by factoring out a "2" tha they all have in common

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0is the equation of the curve "4y^3 +2y 6" ? or is that the 1st derivative of it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats the first derivative..the eqauation of the porabola is xy^2=0

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0..... if all you are looking to do is factor "4y^3+2y6" then I can help.... but as far as it fitting in with all the information that you are leaving out, thatll be up to you :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes i can figure the rest out .. its the factoring that for some reason is hurting me ...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0factor a 2: 2(2y^3 +y 3) = 0 2y^3 +y 3 = 0 is easier to play with

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lets find a "pool" of options to narrow our trail and error with ok" factors of the last #  factors of the first # 1,3  now we can get dirty with it :) 1,2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0we could use long division to try it, but synthetic division is more compact....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lets try y =1 1  2 0 1 3 0 2 2 3  2 2 3 0 < remainder is zero, this is a factor (y1)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the quad facotrs easily now right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0or not at all ;) sqrt(2^2  4(3)(2)) = sqrt(4  24) = sqrt(20) doesnt factor... your only root is y = 1

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0which means, there there is only one critical point; and it is at y=1

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0any of that make sense?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0makes perfect sense.. thanks you much ...
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