anonymous
  • anonymous
without using the integral test directly show that the sum of(1/n) from n=1 to N diverges as N goes to infinity
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
hey 'whats up
anonymous
  • anonymous
\[\sum_{n=1}^{N} (1/n) diverges as N \rightarrow \infty\]
anonymous
  • anonymous
mathgirl

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anonymous
  • anonymous
whats up
anonymous
  • anonymous
trying 2 figurure out this problem...:(
anonymous
  • anonymous
*figure
anonymous
  • anonymous
AWW DONT CRY
anonymous
  • anonymous
hey i know the answer
anonymous
  • anonymous
what grade r u in mathgirl?
anonymous
  • anonymous
really? help me
anonymous
  • anonymous
k whats going on :P
anonymous
  • anonymous
in in uni, 2nd year
anonymous
  • anonymous
i am to
anonymous
  • anonymous
maybe we can hang out and have sex
anonymous
  • anonymous
thats so imature dud..
anonymous
  • anonymous
freak!!
anonymous
  • anonymous
lol shut up andrew garcia
anonymous
  • anonymous
get lost!
anonymous
  • anonymous
If you don't need anything major as a proof, you could simply state that p series only converge if s > 2, and seeing as s = 1 in this problem, s < 2, therefore it does not converge. If you want a more complicated proof: http://www.math.unh.edu/~jjp/proof/proof_n.html
anonymous
  • anonymous
wow that guy is a freak ..
anonymous
  • anonymous
i was jk !!!!!!!!!!!!!!!
anonymous
  • anonymous
hey mathsgirl whats the problem
anonymous
  • anonymous
its at the top...i think i should use the comparison test but im not sure how
anonymous
  • anonymous
mathsygirl im sorry !
anonymous
  • anonymous
really
anonymous
  • anonymous
il help you get the answer mathsgirl
anonymous
  • anonymous
thanks qwer the link is quite good :)
anonymous
  • anonymous
jonathan2...really, get lost!
anonymous
  • anonymous
woow!!!!!!!!!!!!
anonymous
  • anonymous
your nice
anonymous
  • anonymous
You can use the comparison test by testing another divergent series. If that divergent series is always less than 1/n then that implies 1/n is divergent as well.
anonymous
  • anonymous
and a total feather
anonymous
  • anonymous
what a jerk
anonymous
  • anonymous
thanks again qwer
anonymous
  • anonymous
dopeboy...anything to add?

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