What is the axis of symmetry and the x and y intercept of f(x)=x^2-4x

What is the axis of symmetry and the x and y intercept of f(x)=x^2-4x

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y int = 0 becasue there is no constant on the end of your equation

x(x-4) = = gets your x ints
x = 0 and x = 4

the axis of symmetry is where your vertex is; at -b/2a
4/2(1) = 2 x = 2 is your axis of symmetry

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