anonymous
  • anonymous
Find a quadratic equation having the given numbers as solutions. x= -1/2, x=9/2. Answer must be in ax^2+bx+c=0. a>0 and a,b,c do not all have a common factor
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
sols x=-1/2 and x=9/2, so ax^2+bx+c=(x+1/2)(x-9/2)=0 (x+1/2)(x-9/2) =x^2 + 1/2x - 9/2x -9/4 =x^2 - 4x -9/4 so we can see a=1, b=-4, c=-9/4
anonymous
  • anonymous
wow, this is very confusing!!
anonymous
  • anonymous
you have your quadratic equation there right? so a quadratic equation can be factorised into the form of (x+a)(x+b)=0 (eq1) where solutions are -a and -b so you have there -a=-1/2, a=1/2 and -b=9/2, b=-9/2 apply this into (eq1) we get (x+1/2)(x-9/2)=0 expand this you will get another equation in form of ax^2 + bx + c =0 (*) in this case your expansion equation is x^2 - 4x -9/4 = 0 (**) compare (*) and (**) you can see a=1, b=-4, c=-9/4

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