how would you integrate the sqrt of (9-x^2) from -3 to 3 . i tried trig sub with x = to 3 sin theta but i get a wrong answer at the end; it get 0

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how would you integrate the sqrt of (9-x^2) from -3 to 3 . i tried trig sub with x = to 3 sin theta but i get a wrong answer at the end; it get 0

Mathematics
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you will always get a zero.... becuase the left side cancels out the number for the right side
you either need to move the graph itself to the right by 3 units and adjust the equation; or integrate half of it: from 0 to 3 and then double your result.
or you could do F(a) - F(b) instead and take the absolute value

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Other answers:

4 - 4 = 0 -4 -(4) = -8 |-8| = 8
The left side doesnt cancel the right side. It's an even function, you just did the integral wrong.
no is was suposed to use the power reduction formulas for cos squared
after you realize that step the problem is solved
thanks you guys!
huh... i guess I need to review that part ;) thanx space

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