anonymous
  • anonymous
how would you integrate the sqrt of (9-x^2) from -3 to 3 . i tried trig sub with x = to 3 sin theta but i get a wrong answer at the end; it get 0
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
amistre64
  • amistre64
you will always get a zero.... becuase the left side cancels out the number for the right side
amistre64
  • amistre64
you either need to move the graph itself to the right by 3 units and adjust the equation; or integrate half of it: from 0 to 3 and then double your result.
amistre64
  • amistre64
or you could do F(a) - F(b) instead and take the absolute value

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

amistre64
  • amistre64
4 - 4 = 0 -4 -(4) = -8 |-8| = 8
anonymous
  • anonymous
The left side doesnt cancel the right side. It's an even function, you just did the integral wrong.
anonymous
  • anonymous
no is was suposed to use the power reduction formulas for cos squared
anonymous
  • anonymous
after you realize that step the problem is solved
anonymous
  • anonymous
thanks you guys!
amistre64
  • amistre64
huh... i guess I need to review that part ;) thanx space

Looking for something else?

Not the answer you are looking for? Search for more explanations.