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anonymous
 5 years ago
hello anyone can hel[p me
anonymous
 5 years ago
hello anyone can hel[p me

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what do you need help with?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0n2n for n =5 \[n2n for n =5\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so just plug in 5 for n

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you mean \[n^2n\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so if you plug in 5 for n it will look like this: \[5^25\] \[5^2=25\] 255=20

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0when=5 ,n2  n = ____ 2 u put under the line

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm a little confused as to what you are asking let's go to http://www.dabbleboard.com/draw?b=Guest650426&i=0&c=696cc42c34658c69ab2d66582d499fca37aaae0d and then you can draw out your problem on the white board and I can help you better

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just type in the chat box when you are there

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do anyone no this answer 5(x+3) =

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do anyone no this answer 5(x+3) =

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So you have to expand the problem first. You do this by multiplying both of the numbers in the parenthesis by 5 and setting it equal to 0. 5(x+3) 5x+15=0 subtract 15 from both sides 5x=15 divide both sides by 5 x=3
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