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anonymous

  • 5 years ago

hello anyone can hel[p me

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  1. anonymous
    • 5 years ago
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    what do you need help with?

  2. anonymous
    • 5 years ago
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    n2-n for n =5 \[n2-n for n =5\]

  3. anonymous
    • 5 years ago
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    ok so just plug in 5 for n

  4. anonymous
    • 5 years ago
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    do you mean \[n^2-n\]

  5. anonymous
    • 5 years ago
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    yes

  6. anonymous
    • 5 years ago
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    ok so if you plug in 5 for n it will look like this: \[5^2-5\] \[5^2=25\] 25-5=20

  7. anonymous
    • 5 years ago
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    when=5 ,n2 - n = ____ 2 u put under the line

  8. anonymous
    • 5 years ago
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    I'm a little confused as to what you are asking let's go to http://www.dabbleboard.com/draw?b=Guest650426&i=0&c=696cc42c34658c69ab2d66582d499fca37aaae0d and then you can draw out your problem on the white board and I can help you better

  9. anonymous
    • 5 years ago
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    just type in the chat box when you are there

  10. anonymous
    • 5 years ago
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    do anyone no this answer 5(x+3) =

  11. anonymous
    • 5 years ago
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    do anyone no this answer 5(x+3) =

  12. anonymous
    • 5 years ago
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    So you have to expand the problem first. You do this by multiplying both of the numbers in the parenthesis by 5 and setting it equal to 0. 5(x+3) 5x+15=0 subtract 15 from both sides 5x=-15 divide both sides by 5 x=-3

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spraguer (Moderator)
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