anonymous
  • anonymous
hello anyone can hel[p me
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
what do you need help with?
anonymous
  • anonymous
n2-n for n =5 \[n2-n for n =5\]
anonymous
  • anonymous
ok so just plug in 5 for n

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anonymous
  • anonymous
do you mean \[n^2-n\]
anonymous
  • anonymous
yes
anonymous
  • anonymous
ok so if you plug in 5 for n it will look like this: \[5^2-5\] \[5^2=25\] 25-5=20
anonymous
  • anonymous
when=5 ,n2 - n = ____ 2 u put under the line
anonymous
  • anonymous
I'm a little confused as to what you are asking let's go to http://www.dabbleboard.com/draw?b=Guest650426&i=0&c=696cc42c34658c69ab2d66582d499fca37aaae0d and then you can draw out your problem on the white board and I can help you better
anonymous
  • anonymous
just type in the chat box when you are there
anonymous
  • anonymous
do anyone no this answer 5(x+3) =
anonymous
  • anonymous
do anyone no this answer 5(x+3) =
anonymous
  • anonymous
So you have to expand the problem first. You do this by multiplying both of the numbers in the parenthesis by 5 and setting it equal to 0. 5(x+3) 5x+15=0 subtract 15 from both sides 5x=-15 divide both sides by 5 x=-3

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