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anonymous
 5 years ago
Factor f(x) = x^4 + 5x^2  14 completely.
anonymous
 5 years ago
Factor f(x) = x^4 + 5x^2  14 completely.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0let y = x^2 ; it won't factor any further than two quadratics in y.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The answer is supposed to look something like (this probably isnt the answer but for example) : \[(x  \sqrt{7})(x  \sqrt{7})(x + \sqrt{2}i)(x \sqrt{2}i)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Im not sure how to solve for it this way :(

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If you go that far, then so beit. HOWEVER, if you want it in that form (I normally don't) who am I to stop you. First, factor f(x) into two quadratics: Let y = x^2 => f(x) = y^2 + 5y  14 = (y+7)(y2) => f(x) = (x^2+7)(x^22) Then you can factorise these (well, if you call using imaginary numbers factorising :@)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I got \[(x + \sqrt{7}i)(x\sqrt{7}i)(x+\sqrt{2})(x\sqrt{2})\] does that seem right you?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I got \[(x + \sqrt{7}i)(x\sqrt{7}i)(x+\sqrt{2})(x\sqrt{2})\] does that seem right you?
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