## anonymous 5 years ago Let f(x) = x^2 + 7, g(x) =1/(x-2), h(x)=sqrt6x. Find a formula for: g(f(h(x)))

1. anonymous

This means you take the equation for h(x) and put it in place of the "x" in f(x). Simplify that answer. Then, take whatever you got, and put it in place of the x in g(x)

2. anonymous

In other words, you know h(x) = $\sqrt{?}$, so if you put that into f(x), you would get $(\sqrt{6x})^{2}+ 7$

3. anonymous

okay that makes sense thanks

4. anonymous

great