Let f(x) = x^2 + 7, g(x) =1/(x-2), h(x)=sqrt6x. Find a formula for: g(f(h(x)))

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Let f(x) = x^2 + 7, g(x) =1/(x-2), h(x)=sqrt6x. Find a formula for: g(f(h(x)))

Mathematics
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This means you take the equation for h(x) and put it in place of the "x" in f(x). Simplify that answer. Then, take whatever you got, and put it in place of the x in g(x)
In other words, you know h(x) = \[\sqrt{?}\], so if you put that into f(x), you would get \[(\sqrt{6x})^{2}+ 7\]
okay that makes sense thanks

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great

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