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anonymous
 5 years ago
Exponential Equations help?
Determine the exact value of x:
(1/8)^(x3) = 2 * 16^(2x+1)
anonymous
 5 years ago
Exponential Equations help? Determine the exact value of x: (1/8)^(x3) = 2 * 16^(2x+1)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Are you using logarithms to solve?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can it be solved without logarithms??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't know how to solve w/o logs

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay...logarithms are fine then :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Haha :) First, take the log of both sides

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Then apply your log rules...in other words......

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\log (1/8)^{x3}= (x3) \log (1/8)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and \[\log (2 * 16^{2x +1}) = \log 2 + \log 16^{2x+1}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this equals \[\log 2 + (2x+1) \log 16\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so now you have\[(x3) \log (1/8)= \log 2 + (2x + 1) \log 16\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0evaluate the logs and solve the equation for x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0There may be another way to solve, but I'm not sure

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thanks :) ..but can you explain what you mean by evaluate the logs? i've never done them before, really. :S

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, forget all that....i just figured out a better way :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This gives you \[2^{3(x3)}= 2^{1}*2^{4(2x+1)}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0For the exponents, use distributive property

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[2^{3x+9}= 2^{1}*2^{8x +1}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0on the right side, you can combine those by adding expontents

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[2^{3x+9}=2^{8x+2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now, since the bases are equal, this means the exonents are =, so\[3x + 9 = 8x + 2\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Then, solve the equation for x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0haha....that was easier than logs :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yay! this makes so much sense to me. thanks so much :)
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