could anyone explain why limit of [(1/t)-1 when t approaches 0+], is infinity? I don't really get the meaning of t approaching a+/a-. I understand it means approaching from left/right, but how's that related with infinity? Thanks a bunch!
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
since infinity is an abstract concept, we often use approaching infinity to keep the integrity of a mathematical equation. For example if i said x+3y^2 = infinity, then the equation has lost its meaning. What do you assign to x and y to get infinity?
similarly, for t = 0, 1/t = 1/0 which is infinity. So, to describe this, we say 1/t approaches infinity as t approaches 0. t can approach 0 from the right side, 0+ or the left side, 0-
if it approaches from right side of the graph, you get + infinity, if it approaches from left side of graph, you get negative infinity. Infinity can stretch out in both directions.
wait a sec, isn't 1/t just undefined when t=0? Why would it be infinite?