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anonymous
 5 years ago
the equation x^3  6x^2 + 11x  3 = 0 has a solution near x = 0. Use Newton's Method to find an approx value (out of 3 decimal places) for this solution.
anonymous
 5 years ago
the equation x^3  6x^2 + 11x  3 = 0 has a solution near x = 0. Use Newton's Method to find an approx value (out of 3 decimal places) for this solution.

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myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0It says the solution is near x=0. let's use an approximation for the solution. We make the initial guess 1/2.

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0x_1=x_0f(x_0)/f'(x_0)=1/2f(1/2)/f'(1/2)=...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is it x_o  f(x_o) ALL OVER f'(x_o)? Or just f(x_o) / f'(x_o)

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0you don't know the forumla? is that all you need help on? ok well its xf/f'

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0the x is not being divided by f' the f' is just under the f

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So after I plug in the 1/2, is that my answer? Or do I continue to get smaller like 1/4, 1/8, etc?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Also, do I do negatives?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0no it says to do it til you get within 3 decimal points so when you do this you do it over and over until you see the same 3 decimal points repeating

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thanks! Thank you so much. Have a great night!
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