finding derivatives of polar coordinates

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finding derivatives of polar coordinates

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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is there an equations?
x=2cosT y=sinT T=Pi/4
so take the derivative of both with respect to T

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Other answers:

question is fint the equation of the line tangent to the curve by given value
ok so to find M you take the derivative of both functions first then do (Dx/dt)/(dy/dt) which would give u ur Slope equation then plug in Pi/4 for Theta. once get that plug in theta into the x and y funcitons to get ur x and y and then use y-y1=m(x-x1) equation to find tangent line. does that help?
bingo thanks!
no problem!!

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