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anonymous

  • 5 years ago

finding derivatives of polar coordinates

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  1. anonymous
    • 5 years ago
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    is there an equations?

  2. anonymous
    • 5 years ago
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    x=2cosT y=sinT T=Pi/4

  3. anonymous
    • 5 years ago
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    so take the derivative of both with respect to T

  4. anonymous
    • 5 years ago
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    question is fint the equation of the line tangent to the curve by given value

  5. anonymous
    • 5 years ago
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    ok so to find M you take the derivative of both functions first then do (Dx/dt)/(dy/dt) which would give u ur Slope equation then plug in Pi/4 for Theta. once get that plug in theta into the x and y funcitons to get ur x and y and then use y-y1=m(x-x1) equation to find tangent line. does that help?

  6. anonymous
    • 5 years ago
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    bingo thanks!

  7. anonymous
    • 5 years ago
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    no problem!!

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