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anonymous
 5 years ago
integrals...area under the curve?
anonymous
 5 years ago
integrals...area under the curve?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how do we do them...without any rule?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0well if you wanna live by no rule, then it doesnt matter HOW you do them ;) I gotta ask, what do you mean?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0we have a curve with a grid...we need to count the squares and find the area under the curve

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is there any more accurate way to do this than to simply count the squares?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0then you just gotta do your best guess... the area of a "trapazoid" is: (base)([height rightside + height leftside] /2) right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh ok thanks i have another question

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how would i find the average value of f(x) over an interval?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the average of any 2 numbers is add them together and divide by 2 5+8 = 13 13/2 = 6.5 is the average between them

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0how big is the interval?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the average f(x) is the number of each partition added together; then divide by the number of partitions used...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the more subdivision of your interval, the more accurate your average f(x) will be

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0what the integral does is divides the interval into an infinite number of peices then adds them all up to get an exact value ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the interval is 1<=x<=5

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0do you want integration? or the slower way like trapaziodal rule?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0so we have to turn this function into a higher order...... if you dont know the techniques than it aint gonna make alot of sense to you but here they are: sqrt(25  x^2) is a disguised "cos". x = 5 sin(t) so that x^2 = 25sin^2(t) sqrt(25  25sin^2(t)) sqrt(25(1sin^2(t))) = 5cos and then we can integrate:

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0[S] 5cos(t) dt > 5sin(t) +C but since we got and interval we can forgo the +C part.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0and thats the place I get lost at in doing this lol What I need is someone smarter than me to come along and tell me what or why I cant do it like this ;)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0thats my mistake....sqrt(1sin^2) = cos^2...not cos; got it:)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0....nah, I was right to begin with....if you got a show you can watch, now would be the time to do it ;)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0This is what I get for the area 978.338522 and Im like 67% sure im right lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0yep, 98% sure 978.338522
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