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anonymous

  • 5 years ago

how is factoring used to solve quadratic equations. Need to demonstrate the process with an example to show.

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  1. anonymous
    • 5 years ago
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    hi nikki

  2. anonymous
    • 5 years ago
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    factoring is used every day

  3. anonymous
    • 5 years ago
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    Hi

  4. anonymous
    • 5 years ago
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    wazzup?

  5. anonymous
    • 5 years ago
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    you asked the same question twice

  6. anonymous
    • 5 years ago
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    Just having trouble with this class

  7. anonymous
    • 5 years ago
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    ok

  8. anonymous
    • 5 years ago
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    I know...for some reason, it happened

  9. anonymous
    • 5 years ago
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    well if you throw a baseball with initial velocity v0, and initial height y0, you will need to factor to find when it hits the ground

  10. anonymous
    • 5 years ago
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    huh?

  11. anonymous
    • 5 years ago
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    the height of the ball is y = -1/2 gt^2 + vo*t + y0 , where g is your acceleration due to gravity (makes the ball come back to ground)

  12. amistre64
    • 5 years ago
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    you wanna know about factoring right?

  13. anonymous
    • 5 years ago
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    you asked where do we factor? when we solve trajectory problems you dummy

  14. anonymous
    • 5 years ago
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    ask me huh again, i dare you

  15. anonymous
    • 5 years ago
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    wow...that is mean

  16. anonymous
    • 5 years ago
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    im not getting paid after all

  17. anonymous
    • 5 years ago
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    amistre, super hero? wow

  18. anonymous
    • 5 years ago
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    how is factoring used to solve quadratic equations. Need to demonstrate the process with an example to show. Is what I asked...I just do not understand what they want from me...

  19. amistre64
    • 5 years ago
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    solving for any "roots" or "zeros" of an equation, what we are doing is finding all the places that the graph hits the x axis because y = 0 there.

  20. anonymous
    • 5 years ago
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    amistre, its useless

  21. anonymous
    • 5 years ago
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    he will just say "huh"

  22. amistre64
    • 5 years ago
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    with quadratics, the line of the graph bends in such a manner that it can cross the x axis twis, so there may be at most 2 zeros to solve.

  23. anonymous
    • 5 years ago
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    hmmm, i might have misread the question after all, my bad

  24. anonymous
    • 5 years ago
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    amistre, can you solve the surface area of a torus, using integral 2pi y dS?

  25. anonymous
    • 5 years ago
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    amistre, check the discriminant b^2 - 4ac, there are three cases

  26. amistre64
    • 5 years ago
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    for example, can you see the place that this quadratic curve touches the x axis in two spots?

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  27. anonymous
    • 5 years ago
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    amistre, youre like god here. is youre mathematical knowledge proportionate to your score?

  28. anonymous
    • 5 years ago
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    I appreciate all the help...I did not understand what they wanted...I'm sorry if it made anyone mad...

  29. amistre64
    • 5 years ago
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    im just an idiot in disguise ;)

  30. anonymous
    • 5 years ago
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    nikki, no one is mad :)

  31. anonymous
    • 5 years ago
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    sometimes im mean, but im not mad :)

  32. anonymous
    • 5 years ago
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    I am not a guy either...lol

  33. anonymous
    • 5 years ago
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    oh sorry

  34. anonymous
    • 5 years ago
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    wait, so youre a goddess :)

  35. anonymous
    • 5 years ago
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    Its ok...sometimes I just do not get this stuff...I want to...it just does not happen...Not a math person...

  36. anonymous
    • 5 years ago
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    amistre, surface area integrals. driving me nuts!!!

  37. anonymous
    • 5 years ago
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    A mother of 2

  38. anonymous
    • 5 years ago
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    i have it here on twiddla http://www.twiddla.com/521818

  39. amistre64
    • 5 years ago
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    when we factor the quadratic equation we get if "two" component parts that multiplied to get it: for example: x^2 +6x +8 is a quadratic expression right?

  40. anonymous
    • 5 years ago
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    i think the student is lost in the math jargon. it happens

  41. anonymous
    • 5 years ago
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    I think so

  42. amistre64
    • 5 years ago
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    surface area integrals tend to be of the "ln(sec+tan)" variety right?

  43. anonymous
    • 5 years ago
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    I HATE MATH!!!!!!!! Just sayin!

  44. anonymous
    • 5 years ago
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    hmmm, not really , could be, check this link http://www.twiddla.com/521818 i posted the problem

  45. anonymous
    • 5 years ago
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    nikki, you dont hate math. you just want things to be logical. i understand

  46. amistre64
    • 5 years ago
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    Nikki: when we "factor" the quadratic we get this: (x+2)(x+4) = 0 we make it equal to zero because we want to know what x is when y = 0

  47. amistre64
    • 5 years ago
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    cantor; ill check it out in abit ;)

  48. anonymous
    • 5 years ago
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    thanks

  49. anonymous
    • 5 years ago
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    nikki, whats a quadratic equation> what it means to "solve quadratic equation"

  50. anonymous
    • 5 years ago
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    Oh yes...logical would be great:) I am one that needs to get it right now, I am a perfectionist and this is not helping anything, throws me off...very frustrating!

  51. anonymous
    • 5 years ago
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    ok , slow down. ok lets get the jargon straight

  52. anonymous
    • 5 years ago
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    a quadratic equation is generally y = ax^2 + bx + c

  53. anonymous
    • 5 years ago
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    ill show how factoring helps later to solve, but what does it mean to solve a quadratic equation. this is more jargon or math lingo

  54. amistre64
    • 5 years ago
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    Nikki: we know that any number when multiplied by "0" = 0 right? for example: 3(0) = 0 34(0) = 0 r2d2(0)= 0 you with me?

  55. anonymous
    • 5 years ago
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    sure...

  56. anonymous
    • 5 years ago
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    amistre, want to chime in. what it means to "solve quadratic equation"

  57. amistre64
    • 5 years ago
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    cantor, to find their roots :)

  58. anonymous
    • 5 years ago
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    ok

  59. anonymous
    • 5 years ago
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    the roots are the x solutions such that ax^2 + bx + c = 0

  60. amistre64
    • 5 years ago
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    Nikki; then when we have the factored form of a quadratic, we know that one or the other has to equal zero in order for function to equal zero. tell me: (x+4)(0) = 0 ? does (0)(x+2) = 0?

  61. anonymous
    • 5 years ago
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    ok, i got lost there for a second. ok a quadratic equation in x is ax^2 + bx + c = some number, correct? a quadratic function i think would be y = ax^2 + bx + c , because now you have y is a function of x

  62. anonymous
    • 5 years ago
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    ok...I think I got it....hopefully:) Thanks for all your help!

  63. anonymous
    • 5 years ago
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    amistre, ill politely bow out of here, but please check my twiddla

  64. amistre64
    • 5 years ago
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    ill be there shortly, and maybe I can even be helpful ;)

  65. anonymous
    • 5 years ago
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    oh i didnt state the question, one sec

  66. anonymous
    • 5 years ago
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    surface area of a torus. it is generated by circle with radius r , off center. Suppose the circle is centered at (x - R)^2 + y^2 = r^2, and R> r. so the distance from (0,0) to the center of the circle is (R,0) which has radius r. Ok the integral i got is int 2pi y sqrt [ 1+ (dy/dx)^2] = int 2pi sqrt ( r^2 - ( x-R)^2) [ 1 + (-2(x-R)/(2sqrt( r^2 - ( x-R)^2) ^2 ]

  67. anonymous
    • 5 years ago
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    Is this to me?

  68. amistre64
    • 5 years ago
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    Nikki; the factored form allows us to "see" into the quadratic, and know quite easily what the solutions are. (x+4)(x+2) = 0 x = -4 or x = -2 because both these solutions makes one or the other a (0) right?

  69. anonymous
    • 5 years ago
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    yeah

  70. amistre64
    • 5 years ago
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    ack!!...a torus surface..... lol

  71. amistre64
    • 5 years ago
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    Nikki: then that is all ther eis to it, I just hope you can make sense of it between the posting lol

  72. anonymous
    • 5 years ago
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    I am so confused...not sure if it was all for me or for you guys?lol

  73. anonymous
    • 5 years ago
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    well i have two ways to solve it, one way works, the other doesnt, int 2pi y ( 1 + dy/dx^2) dx , that doesnt work, but int 2pi x ( 1 + dx/dy^2) dy that works. not sure why

  74. anonymous
    • 5 years ago
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    nikki, ok i will start over , want to do this? ARE YOU READY!!!

  75. anonymous
    • 5 years ago
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    YES! Sorry...

  76. anonymous
    • 5 years ago
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    oh no im gonna miss jay leno

  77. anonymous
    • 5 years ago
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    ok , uno momento

  78. anonymous
    • 5 years ago
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    I am glad I have DVR

  79. anonymous
    • 5 years ago
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    what do you watch?

  80. anonymous
    • 5 years ago
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    a lot of shows, I really like greys and things like that...so I record them so I do not have to watch all the commercials

  81. amistre64
    • 5 years ago
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    I see the equations..... wheres the torus?

  82. anonymous
    • 5 years ago
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    ok whats a quadratic equation In mathematics, a quadratic equation is a polynomial equation of the second degree. The general form is ax^2 + bx + c = 0

  83. myininaya
    • 5 years ago
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    cantorset, i wrote log3(n)<n as n<3^n for the log proof sorry for interrupting later

  84. anonymous
    • 5 years ago
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    Are you still there?

  85. anonymous
    • 5 years ago
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    hey sorry

  86. anonymous
    • 5 years ago
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    Its ok....I have to figure out an example for this, and I guess I am not getting this as much as I wanted to be or thought...

  87. anonymous
    • 5 years ago
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    give me 5 minutes

  88. anonymous
    • 5 years ago
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    ok....I appreciate your help...I really do.

  89. anonymous
    • 5 years ago
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    I will go check on my daughters

  90. anonymous
    • 5 years ago
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    ok I'm back.....

  91. amistre64
    • 5 years ago
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    welcome back :)

  92. anonymous
    • 5 years ago
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    Thanks! I am trying to figure out how some get this math stuff, and then there is me...who has no idea and thinks I get it and then does not...

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