anonymous
  • anonymous
how is factoring used to solve quadratic equations. Need to demonstrate the process with an example to show.
Mathematics
  • Stacey Warren - Expert brainly.com
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jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
hi nikki
anonymous
  • anonymous
factoring is used every day
anonymous
  • anonymous
Hi

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anonymous
  • anonymous
wazzup?
anonymous
  • anonymous
you asked the same question twice
anonymous
  • anonymous
Just having trouble with this class
anonymous
  • anonymous
ok
anonymous
  • anonymous
I know...for some reason, it happened
anonymous
  • anonymous
well if you throw a baseball with initial velocity v0, and initial height y0, you will need to factor to find when it hits the ground
anonymous
  • anonymous
huh?
anonymous
  • anonymous
the height of the ball is y = -1/2 gt^2 + vo*t + y0 , where g is your acceleration due to gravity (makes the ball come back to ground)
amistre64
  • amistre64
you wanna know about factoring right?
anonymous
  • anonymous
you asked where do we factor? when we solve trajectory problems you dummy
anonymous
  • anonymous
ask me huh again, i dare you
anonymous
  • anonymous
wow...that is mean
anonymous
  • anonymous
im not getting paid after all
anonymous
  • anonymous
amistre, super hero? wow
anonymous
  • anonymous
how is factoring used to solve quadratic equations. Need to demonstrate the process with an example to show. Is what I asked...I just do not understand what they want from me...
amistre64
  • amistre64
solving for any "roots" or "zeros" of an equation, what we are doing is finding all the places that the graph hits the x axis because y = 0 there.
anonymous
  • anonymous
amistre, its useless
anonymous
  • anonymous
he will just say "huh"
amistre64
  • amistre64
with quadratics, the line of the graph bends in such a manner that it can cross the x axis twis, so there may be at most 2 zeros to solve.
anonymous
  • anonymous
hmmm, i might have misread the question after all, my bad
anonymous
  • anonymous
amistre, can you solve the surface area of a torus, using integral 2pi y dS?
anonymous
  • anonymous
amistre, check the discriminant b^2 - 4ac, there are three cases
amistre64
  • amistre64
for example, can you see the place that this quadratic curve touches the x axis in two spots?
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anonymous
  • anonymous
amistre, youre like god here. is youre mathematical knowledge proportionate to your score?
anonymous
  • anonymous
I appreciate all the help...I did not understand what they wanted...I'm sorry if it made anyone mad...
amistre64
  • amistre64
im just an idiot in disguise ;)
anonymous
  • anonymous
nikki, no one is mad :)
anonymous
  • anonymous
sometimes im mean, but im not mad :)
anonymous
  • anonymous
I am not a guy either...lol
anonymous
  • anonymous
oh sorry
anonymous
  • anonymous
wait, so youre a goddess :)
anonymous
  • anonymous
Its ok...sometimes I just do not get this stuff...I want to...it just does not happen...Not a math person...
anonymous
  • anonymous
amistre, surface area integrals. driving me nuts!!!
anonymous
  • anonymous
A mother of 2
anonymous
  • anonymous
i have it here on twiddla http://www.twiddla.com/521818
amistre64
  • amistre64
when we factor the quadratic equation we get if "two" component parts that multiplied to get it: for example: x^2 +6x +8 is a quadratic expression right?
anonymous
  • anonymous
i think the student is lost in the math jargon. it happens
anonymous
  • anonymous
I think so
amistre64
  • amistre64
surface area integrals tend to be of the "ln(sec+tan)" variety right?
anonymous
  • anonymous
I HATE MATH!!!!!!!! Just sayin!
anonymous
  • anonymous
hmmm, not really , could be, check this link http://www.twiddla.com/521818 i posted the problem
anonymous
  • anonymous
nikki, you dont hate math. you just want things to be logical. i understand
amistre64
  • amistre64
Nikki: when we "factor" the quadratic we get this: (x+2)(x+4) = 0 we make it equal to zero because we want to know what x is when y = 0
amistre64
  • amistre64
cantor; ill check it out in abit ;)
anonymous
  • anonymous
thanks
anonymous
  • anonymous
nikki, whats a quadratic equation> what it means to "solve quadratic equation"
anonymous
  • anonymous
Oh yes...logical would be great:) I am one that needs to get it right now, I am a perfectionist and this is not helping anything, throws me off...very frustrating!
anonymous
  • anonymous
ok , slow down. ok lets get the jargon straight
anonymous
  • anonymous
a quadratic equation is generally y = ax^2 + bx + c
anonymous
  • anonymous
ill show how factoring helps later to solve, but what does it mean to solve a quadratic equation. this is more jargon or math lingo
amistre64
  • amistre64
Nikki: we know that any number when multiplied by "0" = 0 right? for example: 3(0) = 0 34(0) = 0 r2d2(0)= 0 you with me?
anonymous
  • anonymous
sure...
anonymous
  • anonymous
amistre, want to chime in. what it means to "solve quadratic equation"
amistre64
  • amistre64
cantor, to find their roots :)
anonymous
  • anonymous
ok
anonymous
  • anonymous
the roots are the x solutions such that ax^2 + bx + c = 0
amistre64
  • amistre64
Nikki; then when we have the factored form of a quadratic, we know that one or the other has to equal zero in order for function to equal zero. tell me: (x+4)(0) = 0 ? does (0)(x+2) = 0?
anonymous
  • anonymous
ok, i got lost there for a second. ok a quadratic equation in x is ax^2 + bx + c = some number, correct? a quadratic function i think would be y = ax^2 + bx + c , because now you have y is a function of x
anonymous
  • anonymous
ok...I think I got it....hopefully:) Thanks for all your help!
anonymous
  • anonymous
amistre, ill politely bow out of here, but please check my twiddla
amistre64
  • amistre64
ill be there shortly, and maybe I can even be helpful ;)
anonymous
  • anonymous
oh i didnt state the question, one sec
anonymous
  • anonymous
surface area of a torus. it is generated by circle with radius r , off center. Suppose the circle is centered at (x - R)^2 + y^2 = r^2, and R> r. so the distance from (0,0) to the center of the circle is (R,0) which has radius r. Ok the integral i got is int 2pi y sqrt [ 1+ (dy/dx)^2] = int 2pi sqrt ( r^2 - ( x-R)^2) [ 1 + (-2(x-R)/(2sqrt( r^2 - ( x-R)^2) ^2 ]
anonymous
  • anonymous
Is this to me?
amistre64
  • amistre64
Nikki; the factored form allows us to "see" into the quadratic, and know quite easily what the solutions are. (x+4)(x+2) = 0 x = -4 or x = -2 because both these solutions makes one or the other a (0) right?
anonymous
  • anonymous
yeah
amistre64
  • amistre64
ack!!...a torus surface..... lol
amistre64
  • amistre64
Nikki: then that is all ther eis to it, I just hope you can make sense of it between the posting lol
anonymous
  • anonymous
I am so confused...not sure if it was all for me or for you guys?lol
anonymous
  • anonymous
well i have two ways to solve it, one way works, the other doesnt, int 2pi y ( 1 + dy/dx^2) dx , that doesnt work, but int 2pi x ( 1 + dx/dy^2) dy that works. not sure why
anonymous
  • anonymous
nikki, ok i will start over , want to do this? ARE YOU READY!!!
anonymous
  • anonymous
YES! Sorry...
anonymous
  • anonymous
oh no im gonna miss jay leno
anonymous
  • anonymous
ok , uno momento
anonymous
  • anonymous
I am glad I have DVR
anonymous
  • anonymous
what do you watch?
anonymous
  • anonymous
a lot of shows, I really like greys and things like that...so I record them so I do not have to watch all the commercials
amistre64
  • amistre64
I see the equations..... wheres the torus?
anonymous
  • anonymous
ok whats a quadratic equation In mathematics, a quadratic equation is a polynomial equation of the second degree. The general form is ax^2 + bx + c = 0
myininaya
  • myininaya
cantorset, i wrote log3(n)
anonymous
  • anonymous
Are you still there?
anonymous
  • anonymous
hey sorry
anonymous
  • anonymous
Its ok....I have to figure out an example for this, and I guess I am not getting this as much as I wanted to be or thought...
anonymous
  • anonymous
give me 5 minutes
anonymous
  • anonymous
ok....I appreciate your help...I really do.
anonymous
  • anonymous
I will go check on my daughters
anonymous
  • anonymous
ok I'm back.....
amistre64
  • amistre64
welcome back :)
anonymous
  • anonymous
Thanks! I am trying to figure out how some get this math stuff, and then there is me...who has no idea and thinks I get it and then does not...

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