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anonymous

  • 5 years ago

6 + 10 x + 14 x^2 what's the GCF here and is it smaller than the smallest coefficient?

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  1. amistre64
    • 5 years ago
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    2 see it as GCF = 2

  2. amistre64
    • 5 years ago
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    1,2,3,6 is the best you can get, what number do the rest have in common with this?

  3. anonymous
    • 5 years ago
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    I'm thinking

  4. amistre64
    • 5 years ago
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    ....think....quieter.....

  5. anonymous
    • 5 years ago
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    It hurts....

  6. anonymous
    • 5 years ago
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    I am not sure...why do I not get this stuff?

  7. amistre64
    • 5 years ago
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    tell me, what are the coeeficients?

  8. anonymous
    • 5 years ago
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    2

  9. amistre64
    • 5 years ago
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    2 is a coefficient?

  10. anonymous
    • 5 years ago
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    I know whatever it is is not smaller then it is, because they are equal to each other...just not sure what number

  11. anonymous
    • 5 years ago
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    it is 6?

  12. amistre64
    • 5 years ago
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    6 is the smallest coefficient..yes; so any factors cannot possibly be larger than 6.

  13. anonymous
    • 5 years ago
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    Thank you so much..sorry about any trouble I caused

  14. amistre64
    • 5 years ago
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    think of it this way: if someone wants you to give them $10 and all you have is $3; what is the most you can give them?

  15. anonymous
    • 5 years ago
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    3

  16. amistre64
    • 5 years ago
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    exactly; so, in this problem of yours we have some numbers that are carrying cash... the largest amount of cash that they have in common cant be greater than the "$6" number right?

  17. anonymous
    • 5 years ago
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    right

  18. amistre64
    • 5 years ago
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    so lets open up that "$6" dollars wallet and see what hes got in there... hes got the following bills: $1, $2, $3 , $6. the rest of the numbers have similar types of cash. but the biggest numbered bill they have in common is a $2.

  19. anonymous
    • 5 years ago
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    I get it....that sounds simple...till you get to the way it looks in front, if they would word the things like you just did, I would be fine...

  20. amistre64
    • 5 years ago
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    the "10" is carrying: $1, $2, $5, $10 the "14" is carrying: $1, $2, $7, $14 the only "bills" they have in common are $2 bills

  21. anonymous
    • 5 years ago
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    Maybe you can help me with the next 2 things, do you have time?

  22. anonymous
    • 5 years ago
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    I wish you were my teacher.....

  23. amistre64
    • 5 years ago
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    i got at most an hour and a half :)

  24. anonymous
    • 5 years ago
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    only 2 small questions left....

  25. anonymous
    • 5 years ago
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    what are the different ways a quadratic polynomial can be factored out. What applies when?

  26. anonymous
    • 5 years ago
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    and.......... x ^ 3 + 2x^2 + x = 0 Can factorization still help solve this equation ? If yes, how ?

  27. anonymous
    • 5 years ago
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    Those are it...If you have time.

  28. amistre64
    • 5 years ago
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    lets dooooo this!!! ... :)

  29. amistre64
    • 5 years ago
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    thats my machoman randy savage impersonation :)

  30. amistre64
    • 5 years ago
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    what are the different ways a quadratic polynomial can be factored out. What applies when? the different ways to factor a quad equation..... well, there is the trial and error method

  31. anonymous
    • 5 years ago
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    I love your enthusiasm:)

  32. amistre64
    • 5 years ago
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    lol

  33. anonymous
    • 5 years ago
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    I think they should put a like button on here!lol

  34. amistre64
    • 5 years ago
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    there is the "completeing the square" method

  35. amistre64
    • 5 years ago
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    hah...i think thats the fan button. they give you cool titles like lifesaver, champion, star...but when you get to 100 and above, they turn you into a sandwich :/

  36. anonymous
    • 5 years ago
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    :( (to the sandwich part) I'm a fan of you:)

  37. anonymous
    • 5 years ago
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    I suck i have no fans

  38. amistre64
    • 5 years ago
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    awww.... thanx :) I hit 200 a few days ago and was hoping for something cool like "turkey club on rye"..but noooooo.....they stuck me with "superhero" lol

  39. anonymous
    • 5 years ago
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    be right back...I need to check on my daughters...

  40. anonymous
    • 5 years ago
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    lol...

  41. anonymous
    • 5 years ago
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    ok..they are fine

  42. amistre64
    • 5 years ago
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    the four most used methods to factor quadratics are: Factoring Factor by Grouping Quadratic Formula Completing the Square

  43. anonymous
    • 5 years ago
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    Does that have to do with the 1st question

  44. amistre64
    • 5 years ago
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    When do we use them? dunno really. Factoring is just splitting it up into its basic components... that can be done if its easy to recognize

  45. amistre64
    • 5 years ago
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    yeah sure...maybe :)

  46. amistre64
    • 5 years ago
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    by grouping generally ocuurs when there are more than 3 terms. we group them into pairs and factor them seperatley

  47. amistre64
    • 5 years ago
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    the quad formula is used when we just dont have time or patience to do the other ways :)

  48. amistre64
    • 5 years ago
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    and completing the square is just the long hand version of the quad formula, I guess you use it when you cant recall the quadratic formula :)

  49. anonymous
    • 5 years ago
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    Now to the 2nd question

  50. amistre64
    • 5 years ago
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    x ^ 3 + 2x^2 + x = 0 Can factorization still help solve this equation ? If yes, how ? Yes, if we can notice that all the terms include an "x" factor then we can remove it and do our quadratic techniques on the remaining terms like this: x ^ 3 + 2x^2 + x = 0 x(x^2 +2x +x) = 0 x (x+1)(x+1) = 0 x = 0 or x = -1

  51. amistre64
    • 5 years ago
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    that little straggling +x should be a +1....

  52. amistre64
    • 5 years ago
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    x(x^2 +2x +x) = 0 <- right in there x(x^2 +2x +1) = 0 x (x+1)(x+1) = 0

  53. anonymous
    • 5 years ago
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    ok, Now I am confused...

  54. anonymous
    • 5 years ago
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    lol...story of my life

  55. amistre64
    • 5 years ago
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    tell me whats got you confused :)

  56. anonymous
    • 5 years ago
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    about the straggling....

  57. amistre64
    • 5 years ago
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    I had a typo in there; that x^2 +2x +[x] <- right there. it should have been: x^2 +2x +1

  58. anonymous
    • 5 years ago
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    Thank you got it! I will probably be on again tomorrow.....I have this stuff all week and get really frustrated! Thanks for all your help! You are great! I am sure you are better then a sandwich:)

  59. amistre64
    • 5 years ago
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    thanx :) take care ;)

  60. anonymous
    • 5 years ago
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    You too

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