anonymous
  • anonymous
6 + 10 x + 14 x^2 what's the GCF here and is it smaller than the smallest coefficient?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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amistre64
  • amistre64
2 see it as GCF = 2
amistre64
  • amistre64
1,2,3,6 is the best you can get, what number do the rest have in common with this?
anonymous
  • anonymous
I'm thinking

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amistre64
  • amistre64
....think....quieter.....
anonymous
  • anonymous
It hurts....
anonymous
  • anonymous
I am not sure...why do I not get this stuff?
amistre64
  • amistre64
tell me, what are the coeeficients?
anonymous
  • anonymous
2
amistre64
  • amistre64
2 is a coefficient?
anonymous
  • anonymous
I know whatever it is is not smaller then it is, because they are equal to each other...just not sure what number
anonymous
  • anonymous
it is 6?
amistre64
  • amistre64
6 is the smallest coefficient..yes; so any factors cannot possibly be larger than 6.
anonymous
  • anonymous
Thank you so much..sorry about any trouble I caused
amistre64
  • amistre64
think of it this way: if someone wants you to give them $10 and all you have is $3; what is the most you can give them?
anonymous
  • anonymous
3
amistre64
  • amistre64
exactly; so, in this problem of yours we have some numbers that are carrying cash... the largest amount of cash that they have in common cant be greater than the "$6" number right?
anonymous
  • anonymous
right
amistre64
  • amistre64
so lets open up that "$6" dollars wallet and see what hes got in there... hes got the following bills: $1, $2, $3 , $6. the rest of the numbers have similar types of cash. but the biggest numbered bill they have in common is a $2.
anonymous
  • anonymous
I get it....that sounds simple...till you get to the way it looks in front, if they would word the things like you just did, I would be fine...
amistre64
  • amistre64
the "10" is carrying: $1, $2, $5, $10 the "14" is carrying: $1, $2, $7, $14 the only "bills" they have in common are $2 bills
anonymous
  • anonymous
Maybe you can help me with the next 2 things, do you have time?
anonymous
  • anonymous
I wish you were my teacher.....
amistre64
  • amistre64
i got at most an hour and a half :)
anonymous
  • anonymous
only 2 small questions left....
anonymous
  • anonymous
what are the different ways a quadratic polynomial can be factored out. What applies when?
anonymous
  • anonymous
and.......... x ^ 3 + 2x^2 + x = 0 Can factorization still help solve this equation ? If yes, how ?
anonymous
  • anonymous
Those are it...If you have time.
amistre64
  • amistre64
lets dooooo this!!! ... :)
amistre64
  • amistre64
thats my machoman randy savage impersonation :)
amistre64
  • amistre64
what are the different ways a quadratic polynomial can be factored out. What applies when? the different ways to factor a quad equation..... well, there is the trial and error method
anonymous
  • anonymous
I love your enthusiasm:)
amistre64
  • amistre64
lol
anonymous
  • anonymous
I think they should put a like button on here!lol
amistre64
  • amistre64
there is the "completeing the square" method
amistre64
  • amistre64
hah...i think thats the fan button. they give you cool titles like lifesaver, champion, star...but when you get to 100 and above, they turn you into a sandwich :/
anonymous
  • anonymous
:( (to the sandwich part) I'm a fan of you:)
anonymous
  • anonymous
I suck i have no fans
amistre64
  • amistre64
awww.... thanx :) I hit 200 a few days ago and was hoping for something cool like "turkey club on rye"..but noooooo.....they stuck me with "superhero" lol
anonymous
  • anonymous
be right back...I need to check on my daughters...
anonymous
  • anonymous
lol...
anonymous
  • anonymous
ok..they are fine
amistre64
  • amistre64
the four most used methods to factor quadratics are: Factoring Factor by Grouping Quadratic Formula Completing the Square
anonymous
  • anonymous
Does that have to do with the 1st question
amistre64
  • amistre64
When do we use them? dunno really. Factoring is just splitting it up into its basic components... that can be done if its easy to recognize
amistre64
  • amistre64
yeah sure...maybe :)
amistre64
  • amistre64
by grouping generally ocuurs when there are more than 3 terms. we group them into pairs and factor them seperatley
amistre64
  • amistre64
the quad formula is used when we just dont have time or patience to do the other ways :)
amistre64
  • amistre64
and completing the square is just the long hand version of the quad formula, I guess you use it when you cant recall the quadratic formula :)
anonymous
  • anonymous
Now to the 2nd question
amistre64
  • amistre64
x ^ 3 + 2x^2 + x = 0 Can factorization still help solve this equation ? If yes, how ? Yes, if we can notice that all the terms include an "x" factor then we can remove it and do our quadratic techniques on the remaining terms like this: x ^ 3 + 2x^2 + x = 0 x(x^2 +2x +x) = 0 x (x+1)(x+1) = 0 x = 0 or x = -1
amistre64
  • amistre64
that little straggling +x should be a +1....
amistre64
  • amistre64
x(x^2 +2x +x) = 0 <- right in there x(x^2 +2x +1) = 0 x (x+1)(x+1) = 0
anonymous
  • anonymous
ok, Now I am confused...
anonymous
  • anonymous
lol...story of my life
amistre64
  • amistre64
tell me whats got you confused :)
anonymous
  • anonymous
about the straggling....
amistre64
  • amistre64
I had a typo in there; that x^2 +2x +[x] <- right there. it should have been: x^2 +2x +1
anonymous
  • anonymous
Thank you got it! I will probably be on again tomorrow.....I have this stuff all week and get really frustrated! Thanks for all your help! You are great! I am sure you are better then a sandwich:)
amistre64
  • amistre64
thanx :) take care ;)
anonymous
  • anonymous
You too

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