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anonymous
 5 years ago
find form of a particular solution of the follow equation.. y''+11'+24y=6sin(3t)e^8t
anonymous
 5 years ago
find form of a particular solution of the follow equation.. y''+11'+24y=6sin(3t)e^8t

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oops, equation should be as follow \[y''+11y'+24y=6\sin(3t)^{8t}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So you want to find the homogenous solution first to ensure that when you are trying to find a particular solution, you don't get any repeated solutions. Then I would probably use the method of undetermined coefficients if I were solving. Normally for sin(t) the particular solution looks something like Asin(t)+Bcos(t).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I just need to find form, don't need to solve it or anything Roots are as follow r1=8 and r2=3 so \[Yc=C1e ^{8t}+C2e ^{3t}\] and \[Yp=(Acoos(3t)+Bsin(3t))^{8t} is wrong?\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I would have the 8t exponent on both sin and cos, separately not the quantity.
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