the center for disease control reports that 24.8 percent of californians are obese. a sample of 112 california residents is taken. what is the probability that over 30 percent of the sample is obese?

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the center for disease control reports that 24.8 percent of californians are obese. a sample of 112 california residents is taken. what is the probability that over 30 percent of the sample is obese?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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so basically i know the mean is 27.78 and the std deviation is 4.57...now what
30% of 112 is 33.6 now you want to find out how many std dev's away this is from the mean z = (33.6-27.78)/4.57 = 1.27 now you have to look in a stats z table for probabilities of the standard normal distribution 1 - P(Z<= 1.27)

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