anonymous
  • anonymous
-(pi/4)sin(pix/4) solve for x, x >(or equal to) 0 x <(or equal to) 10 and i should end up with x= 0,4,8 how does that work?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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dumbcow
  • dumbcow
is there any other info? i think it should be equal to something in order to solve for x
anonymous
  • anonymous
equal to 0 sorry
dumbcow
  • dumbcow
wait nevermind its -(pi/4)sin(pi*x/4) = 0 divide by -pi/4 on both sides leaving sin(pi*x/4) = 0 now think about the graph of the sin function it is only zero at x=0,pi,2pi...

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anonymous
  • anonymous
ohhhh but then i get where it is 0. im not gettting that once i get to sin(pi*x/4) what does the pi/4 contribute? idk if im stating that correctly
dumbcow
  • dumbcow
think of it this way say y = pi*x/4 we know sin(y) = 0 at y=0,pi,2pi so set up three equation pix/4 = 0 or pi or 2pi and solve for x
anonymous
  • anonymous
oh ok, thats what i did wrong. i solved for 0, but i forgot that sin is 0 at pi and 2pi. and that i need to account for that too. thank you sooo much!
dumbcow
  • dumbcow
your welcome :)

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