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anonymous
 5 years ago
let f(x)=2x^23x +1
f'(x)=lim f(x+h) f(x)/h
h>0
anonymous
 5 years ago
let f(x)=2x^23x +1 f'(x)=lim f(x+h) f(x)/h h>0

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dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0Replace x with (x+h) > f(x+h) = 2(x+h)^2  3(x+h) + 1 Expand > f(x+h) = 2x^2 + 4xh + 2h^2  3x  3h +1 subtract original function >(2x^2+4xh+2h^23x3h+1)  (2x^23x+1) add like terms **Notice how some terms will cancel >4xh + 2h^23h Factor out an h > h(4x + 2h  3) This is important because now we can cancel the h in the denominator Now reevaluate the lim of (4x + 2h  3) as h>0 lim = 4x 3 Hope this helps
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