anonymous
  • anonymous
find the x intercept of f(x)= 2x^3-15x^2+24x+19?
Mathematics
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
\[1/2 (5-(3 3^(2/3))/(11-2 \sqrt(10))^(1/3)-(3 (11-2 \sqrt(10)))^(1/3)) \]
anonymous
  • anonymous
x~~-0.571767
anonymous
  • anonymous
x = 1/2 (5-(3 3^(2/3))/(11-2 sqrt(10))^(1/3)-(3 (11-2 sqrt(10)))^(1/3))

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Got it?
anonymous
  • anonymous
just tried, but i still dont get it.. what is the formula you used?
anonymous
  • anonymous
http://en.wikipedia.org/wiki/Horner_scheme#Polynomial_root_finding
anonymous
  • anonymous
This link will take you directly to the root finding portion, no need to scroll any further
anonymous
  • anonymous
alright, thanks a lot!
anonymous
  • anonymous
You are welcome
anonymous
  • anonymous
By the way, whats your present level?
anonymous
  • anonymous
I mean is horner scheme in the scope of your syllabus
anonymous
  • anonymous
No its not.. but i ll try find some other websites to guide me through.. thanks for the help anyway!

Looking for something else?

Not the answer you are looking for? Search for more explanations.