anonymous
  • anonymous
a large pump can empty a swimming pool in 100 hours, whereas a small pump can empty the pool in 160 hours. How long will it take to empty the pool if both pumps are used?
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
do u have the answer? I found ~61.54hrs. If that's right then I think I can tell u how.
anonymous
  • anonymous
I can't figure it out at all. I've been stuck on this one for a while :(
anonymous
  • anonymous
but do you have the numerical answer? Because if my answer's wrong so there's no point to show the method

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anonymous
  • anonymous
it says 62
anonymous
  • anonymous
ok, so let's call the tank capacity V (litres), flow rate through large pump F1 and through small pump F2. t1= 100, t2= 160 For pump 1, flow rate F1=V/t1=V/100 (litres/hr) For pump 2, flow rate F2=V/t2=V/160 (litres/hr) when 2 pumps run at the same time, we have total flow rate, say F, equal to F1+F2 so F=F1+F2=V/100+V/160=(13V)/800 so the time needed is t = V/F = V/ ((13V)/800)=800/13~61.54~62hrs hope that clear enough :)
anonymous
  • anonymous
Thanks! just one question: how did u get the 13?
anonymous
  • anonymous
calculator? lol 1/100+1/160= 8/800+5/800 =13/800
anonymous
  • anonymous
oh I understand now. Thanks so much for your help. You're a lifesaver!
anonymous
  • anonymous
ur welcome

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