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do u have the answer? I found ~61.54hrs. If that's right then I think I can tell u how.
I can't figure it out at all. I've been stuck on this one for a while :(
but do you have the numerical answer? Because if my answer's wrong so there's no point to show the method
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it says 62
ok, so let's call the tank capacity V (litres), flow rate through large pump F1 and through small pump F2. t1= 100, t2= 160
For pump 1, flow rate F1=V/t1=V/100 (litres/hr)
For pump 2, flow rate F2=V/t2=V/160 (litres/hr)
when 2 pumps run at the same time, we have total flow rate, say F, equal to F1+F2
so the time needed is t = V/F = V/ ((13V)/800)=800/13~61.54~62hrs
hope that clear enough :)
Thanks! just one question: how did u get the 13?
1/100+1/160= 8/800+5/800 =13/800
oh I understand now. Thanks so much for your help. You're a lifesaver!