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anonymous
 5 years ago
HOW TO DERIVE HELP ME PLEASE
anonymous
 5 years ago
HOW TO DERIVE HELP ME PLEASE

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0have you learned limits, limit based formula, derivative rules ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have no idea i just want to learn something ..please anyone can?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0or anyone can give some easy example with step by step.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0.... uhm... thats not going to be very easy, check out pauls online notes

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0differentiation takes quite a bit of prior knowledge

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its was my prof fault he teach very fast...i have some background all i need some example with steps in deriving tnx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ah ok, so you understand what a derivative is by defenition, just not how to find it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so the limit based formula is: \[(f(x+\Delta x)f(x)) \div \Delta x\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is just a rewritten formula for slope or dy/dx (y1y2)/(x1x2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0because x1x2 is delta x or written as \[\Delta x\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the symbol \[\Delta x\] is used. the top is just y2y1. y2 is the function of your second x aka f(x2) so that can be written as the function of your first x plus the distance between your first and second x, which just gives you the function of your second x.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the symbol \[\Delta x\] is used. the top is just y2y1. y2 is the function of your second x aka f(x2) so that can be written as the function of your first x plus the distance between your first and second x, which just gives you the function of your second x.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but the formula for slope is y2 MINUS y1 so you we say f(x+deltax) minus f(x) which is just y2 minus y1 aka f(x+ deltax)f(x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hence we get that (y2y1)/(x2x1) = dy/dx = (f(x2)f(x1)/(x2x1) = (f(x+dx)f(x))/dx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that is the slope formula rewritten in terms of x. when you plug in two points you will get your slope between them, the point of a derivative is the INSTANT rate of change also known as the slope at an INSTANT in time, x usually represents time so its the slope of the line when x is the same. BUT if x is the saem you end up with 0/0. hence the limit comes in, because x cannot be EXACTLY the same, we make it so that its incredible close in value, aka make it so that x2x1 is almost 0, which is the same as making delta x almost 0 aka taking the limit as delta x goes to 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0a little tnanks arman i guess need to read more here,, is this conversation is automatically saves to my profile?? im new here im from philippine and i cant speak english well tnx again

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ill post a picture of finding the derivative of x^3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wtf is that, stupid school computers

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0rofl i dont even know that kid
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