Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

Looking for something else?

Not the answer you are looking for? Search for more explanations.

- anonymous

for: (10x-3)/(-2x+4)
I got 1st derivative as 34/(-2x+4)^2
is that correct?
Next I need to find the Critical Number(s).
Would that be x=2?

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions.

Get your **free** account and access **expert** answers to this and **thousands** of other questions

- anonymous

- chestercat

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- amistre64

your 1st derivative will never be zero, so it has no critical numbers..

- amistre64

it is undefined at x=2, but I would have to read up on that to see if it matter :)

- anonymous

Amistre64, after you are done with this one, could you please take a look at the http://openstudy.com/groups/mathematics#/updates/4da5d0a9d6938b0b2e74a24d

Looking for something else?

Not the answer you are looking for? Search for more explanations.

- anonymous

how do u go about it?

- amistre64

check out your f(x) for starters; whats its domian?

- amistre64

is it defined at x=2?

- amistre64

if not, then what would the slope of a none existent point be?

- anonymous

how is f(x)=2?

- amistre64

not f(x) = 2; but what is the value of f(2)?
(10x-3)/(-2x+4)
(10(2)-3)/(-2(2)+4)
(20-3)/(-4+4)
17/0 is f(2); which means that there is no value for f(2) to begin with. it has no slope since it is not a part of the graph, or the equation.
f'(2) fails to exists because there is no point at f(2) in order to evaluate.

- anonymous

is two the answer now?

- anonymous

I thought that the x=2 was not a critical number because it cannot be 0 in the den

- anonymous

so if there is no critical number then to give the intervals of concavity, would I still test the x=2?

- amistre64

there is no concavity at x=2 simply becasue x=2 has no value to the equation. If you have nothing to examine, then you simply can examine it :)

- amistre64

like this if I see it correctly

- anonymous

yes that is what my graph looks like. So on my work the question, I need to find Intervals of increase and decrease, so should I just say there are not any?

- amistre64

the graph is increaseing on the interval (-inf,2)
the graph is decreasing on the interval (2,inf)

- anonymous

ok on the graph you sent above are you using both of the lines. I don't see the increasing at (-inf,2) and decreasing on interval (2,inf).
Looking at it I would want to write (-inf,2) increasing and (2,inf) increasing

- amistre64

hmm..... now that you mention it.....
if we start at the left and move right, the slope of our line is increaseing as we mover from -inf to 2. until at 2 it hits an unknown.....
we hop over the line and the slope begins to decrease, gets less steep as we continue to move from 2 out to inf.
So I was right, its increaseing on the left, and decreasing on the right.

- amistre64

the left is concave up, and the right is concave down.... but i havent really checked the 2nd derivative to prove it yet :)

- amistre64

one thing I notice tho is that the second derivative is always positive...which means the the slope is always in the positive condition, no matter how flat it gets, its always a positive slope.

Looking for something else?

Not the answer you are looking for? Search for more explanations.