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anonymous
 5 years ago
Two electrical resistors (one of variable resistance x and one with fixed resistance R1) are put in parallel into a circuit. The combined resistance R, of those two resistors is given by the formula (1/R) = (1/x) + (1/R1). Solve this equation for R. Your answer will be a rational function in x and will include the constant R1. Determine the horizontal asymptote of this function when R1=2000 ohms and then answer the question: As the resistance of x approaches infinity, what is the combined resistance of the two resistors parallel?
anonymous
 5 years ago
Two electrical resistors (one of variable resistance x and one with fixed resistance R1) are put in parallel into a circuit. The combined resistance R, of those two resistors is given by the formula (1/R) = (1/x) + (1/R1). Solve this equation for R. Your answer will be a rational function in x and will include the constant R1. Determine the horizontal asymptote of this function when R1=2000 ohms and then answer the question: As the resistance of x approaches infinity, what is the combined resistance of the two resistors parallel?

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radar
 5 years ago
Best ResponseYou've already chosen the best response.0First part. Since we are dealing with only two resistors, R1 and Rx we can use the product over sum to obtain the equivalent resistance R. R=(R1)(Rx)/(R1 + Rx). For the second part where R1=2000 Ohms and Rx is allowed to increase without limit, R will approach a value of 2,000 Ohms

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Please note when only two resistors are connected in parallel Rtotal= 1(1/R1 + 1/R2) which will work down to being product over sum Rtotal = R1R2/(R1+R2)
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