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anonymous
 5 years ago
The company discovered that it costs $45 to produce 4 camera cases, $257 to produce 7 camera cases, and $792 to produce 12 camera cases. Using quadratic function, find the cost of producing 1 camera case.
anonymous
 5 years ago
The company discovered that it costs $45 to produce 4 camera cases, $257 to produce 7 camera cases, and $792 to produce 12 camera cases. Using quadratic function, find the cost of producing 1 camera case.

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0How we play in the matrix..... its the same as the other one I just did but without the letters cluttering it up

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(4,45) (7,257) (12,792) 16x^2 +4x +c = 45 49x^2 +7x +c = 257 144x^2 +12x +c= 792  16 4 1  45   49 7 1  257  144 12 1  792  is the setup

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0 16 4 1  45  (1/16)  1 1/4 1/16  45/16   49 7 1  257  144 12 1  792   1 1/4 1/16  45/16  (49)  49 7 1  257  49 49/4 49/16  2205/16   49 28/4 16/16  4112/16    0 21/4 33/16  1907/16    1 1/4 1/16  45/16  (144) 144 12 1  792  144 144/4 144/16  6480/16  144 48/4 16/16  12672/16    0 96/4 128/16  6192/16  

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0 21/4 33/16  1907/16  (4/21)  96/4 128/16  6192/16   1 33/84  1907/84  (96/4)  96/4 128/16  6192/16   96/4 66/7  3814/7   96/4 56/7  2709/7    0 10/7  1105/7    10/7  1105/7  (7/10)  1  221/2  c = 110.5

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0 21/4 33/16  1907/16   0 1  1105/10  (33/16)  21/4 33/16  3814/32   0 33/16  7293/32    21/4 0  3479/32  (4/21)  1 0  3479/168  b = 3479/168 c = 1105/10 its quicker on paper, and less mistakes... ill do it up and give you and answer ;)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.01 case costs $18.67 cents; if I did it right... and I have my doubts with it cause of all the fractions, but thats my best guess :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0my computer just froze & shut everything down _

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Another approach to this problem is to use a curve fitting program. The general form of a quadratic equation is: y(x) = a*x^2 + b*x + c. Given a set of data, the curve fitting program will calculate the optimum values for the constants a, b and c using a "least squares" method. Refer to: http://mathworld.wolfram.com/LeastSquaresFitting.html Let y(x) be equal to the cost to produce a batch of x camera cases. From three direct measurements the company had determined that the cost to produce a batch of 4, 7 and 12 camera cases was 45, 257 and 792 dollars respectively. The company wants to know the approximate cost to produce 1 case based on their past production experience. The following Mathematica 8 statement will compute the values for a, b and c for this problem. Fit[{{4, 45}, {7, 257}, {12, 792}}, {1, x, x^2}, x] If the reader has no access to Mathematica 8, then copy and past the above into the "=" input box at www.WolframAlpha.com

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The result is 4.54167 x^2 + 20.7083 x 110.5 and evaluated at x=1 is 85.25 If the numbers above are rationalized,that is, made into fractions, the f[x] can be written as: \[ \frac{109}{24}x{}^{\wedge}2+\frac{497}{24}x\frac{221}{2} \] Refer to the attachment, CameraCase.pdf, which is a plot of f(x). The plot shows that any batch less than 4 is a looser.
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