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anonymous
 5 years ago
deriviative of y= Ae^t (Sint  cost)
anonymous
 5 years ago
deriviative of y= Ae^t (Sint  cost)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What do you mean? A is a constant yes

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0y=A(e^t)(sintcost) y=A(e^t)sint + A(e^t)cost y'=Ad/dt((e^t)sint)+Ad/dt((e^t)cost) d/dt ((e^t)sint) =(e^t)cost + (e^t)sint d/dt ((e^t)cost)=(e^t)(sint) + (e^t)cost y'=A(((e^t)cost + (e^t)sint)+(e^t)(sint) + (e^t)cost) y'=A((e^t)cost + (e^t)sint + (e^t)(sint)  (e^t)cost) y'=A(2(e^t)cost)=2A(e^t)cost

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ahhhh yes thanks alot :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0btw can you guess what level calculus this is?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I would say end of 1st year uni or beginning of 2nd year, if that's what you mean by level.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im doing this in my senoir year of highschool :( my teacher is crazyyyy

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I got expelled :D:D:D hate those highweeded teachers
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