anonymous
  • anonymous
deriviative of y= -Ae^-t (Sint - cost)
Mathematics
  • Stacey Warren - Expert brainly.com
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
A constant?
anonymous
  • anonymous
What do you mean? A is a constant yes
anonymous
  • anonymous
y=-A(e^-t)(sint-cost) y=-A(e^-t)sint + A(e^-t)cost y'=-Ad/dt((e^-t)sint)+Ad/dt((e^-t)cost) d/dt ((e^-t)sint) =(e^-t)cost + (-e^-t)sint d/dt ((e^-t)cost)=(e^-t)(-sint) + (-e^-t)cost y'=A(-((e^-t)cost + (-e^-t)sint)+(e^-t)(-sint) + (-e^-t)cost) y'=A(-(e^-t)cost + (e^-t)sint + (e^-t)(-sint) - (e^-t)cost) y'=A(-2(e^-t)cost)=-2A(e^-t)cost

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anonymous
  • anonymous
Ahhhh yes thanks alot :)
anonymous
  • anonymous
no prob
anonymous
  • anonymous
btw can you guess what level calculus this is?
anonymous
  • anonymous
I would say end of 1st year uni or beginning of 2nd year, if that's what you mean by level.
anonymous
  • anonymous
im doing this in my senoir year of highschool :( my teacher is crazyyyy
anonymous
  • anonymous
I got expelled :D:D:D hate those highweeded teachers

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