anonymous
  • anonymous
how do you slove 4a^4-5a^2+1=0
Mathematics
katieb
  • katieb
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amistre64
  • amistre64
solve for a subsituted variable really; claim that x=a^2 and x^2 = a^4 then solve for x... 4x^2 -5x +1 = 0 (x-1/4)(x-4/4) x = 1/4 and x = 1
amistre64
  • amistre64
since x = a^2 1/4 = a^2 +-sqrt(1/4) = a +- 1/2 = a
myininaya
  • myininaya
very good you super hero!

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amistre64
  • amistre64
1 = a^2 1 = a
amistre64
  • amistre64
lol ..... that aint kyptonite you got in there is it :)
myininaya
  • myininaya
it doesnt matter if you arent superman
amistre64
  • amistre64
they call me ..MISTER PIG!!!....AAAAAAAHHHHHHHHHHHHHH!!!!!!!!!!
amistre64
  • amistre64
so a = +- 1/2 and or +- 1 and maybe some other things that I forgot to remember..
anonymous
  • anonymous
thanks!!

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