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anonymous

  • 5 years ago

how do you solve 4x^(2/3)+16x^(1/3)=-15

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  1. anonymous
    • 5 years ago
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    try to move the 4 and the 16 to the other side of the = sign, for a start

  2. anonymous
    • 5 years ago
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    try to move the 4 and the 16 to the other side of the = sign, for a start

  3. anonymous
    • 5 years ago
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    actually thats a good question, i dont know how to do it. anyone?

  4. anonymous
    • 5 years ago
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    I got it, saw this in chat but idk why i cant join the chat. Anyone interested?

  5. anonymous
    • 5 years ago
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    yes!

  6. anonymous
    • 5 years ago
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    you let a=x^(1/3) so equation becomes 4a^2+16a+15=0 solve that get a=-3/2 or a=-5/2 case 1: a=-3/2 so x^(1/3)=-3/2 x=(-3/2)^3 case 2: similar

  7. anonymous
    • 5 years ago
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    ok, but can you put a step in going from your 2nd line to the third? cause thats also getting me stuck

  8. anonymous
    • 5 years ago
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    ok x^(2/3)=(x^(1/3))^2=a^2 4a^2+16a+15 =4a^2+6a+10a+15 =2a(2a^2+3) + 5(2a+3) =(2a^2+3)(2a+5) hope that's clear enough

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