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anonymous
 5 years ago
what is a pseries?
anonymous
 5 years ago
what is a pseries?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it is a summation the is set up (An)^n\[\sum_{?}^{?}(A _{n})^n\], it's a series that is made to a power

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0could you help me find p on a pseries

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0let me take a look at it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hold on let me write the problem

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sum_{n=1}^{\infty} \sqrt[3]{(6n^56n^3+7n)} / (6n^5+2n^44)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0gee whiz I wan't expecting that there, give me a few minutes

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no problem, is that the 3rd root over the numerator?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes sorry it was hard to make it look like it was only over the numerator ha

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so they want you to resolve this thing down to some ort of series all taken up to the same power then?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0heres an example.... 1/n and p=1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and if it was \[7/\sqrt{n}\] p=1/2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I could see\[\sum_{?}^{?}(1/(6n^5+2n^44))*(6n^56n^3+7n)^(1/3)\] that is to the (1/3) toward the end there. In that case the power it is taken to is (1/3). I just don't see anyway of reducing the n's down so it is more clear. I guess if I were answering it, I would say (1/3) is the only determinable power. It's not as if the numerator and denominater have like bases to see it being anything else. Neither one of them are factorable from wht I can see.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0unless in some sick way they are expection 11/3 = 2/3, but I really can't see that, because like I said the bases would have to be the same.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I ws thinking you had something vageuly reducible that could be taken up to a single power. I've had stuff like that thrown at me, but jsut to say what the power is alone, is different. Sorry I could not be more help.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you did help me, thank you :)
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