what is a p-series?

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

what is a p-series?

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

it is a summation the is set up (An)^n\[\sum_{?}^{?}(A _{n})^n\], it's a series that is made to a power
could you help me find p on a p-series
let me take a look at it.

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

hold on let me write the problem
\[\sum_{n=1}^{\infty} \sqrt[3]{(6n^5-6n^3+7n)} / (6n^5+2n^4-4)\]
gee whiz I wan't expecting that there, give me a few minutes
lol thank you
no problem, is that the 3rd root over the numerator?
yes sorry it was hard to make it look like it was only over the numerator ha
so they want you to resolve this thing down to some ort of series all taken up to the same power then?
heres an example.... 1/n and p=1
and if it was \[7/\sqrt{n}\] p=1/2
I could see\[\sum_{?}^{?}(1/(6n^5+2n^4-4))*(6n^5-6n^3+7n)^(1/3)\] that is to the (1/3) toward the end there. In that case the power it is taken to is (1/3). I just don't see anyway of reducing the n's down so it is more clear. I guess if I were answering it, I would say (1/3) is the only determinable power. It's not as if the numerator and denominater have like bases to see it being anything else. Neither one of them are factorable from wht I can see.
unless in some sick way they are expection 1-1/3 = 2/3, but I really can't see that, because like I said the bases would have to be the same.
*expecting
lol idk either
I ws thinking you had something vageuly reducible that could be taken up to a single power. I've had stuff like that thrown at me, but jsut to say what the power is alone, is different. Sorry I could not be more help.
you did help me, thank you :)
no problem

Not the answer you are looking for?

Search for more explanations.

Ask your own question