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anonymous
 5 years ago
Find the limit if it exists:
lim x>infinity
x[ln(x+4)ln(x)]
anonymous
 5 years ago
Find the limit if it exists: lim x>infinity x[ln(x+4)ln(x)]

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ive gotten this far: x/(1/x+4)(1/x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, well the term ln(x) as it approaches infinity is infinity

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so for the part of the brackets you'll have a number that is positive and approaching infinity

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so, that means the entire term is approaching positive infinity

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah you don't really need to do any work here. You know that ln(x+4) will be greater than ln(x) for all x. Therefore even if the difference between them was something very small, constant, and positive, the x out in front would grow without bound. So the whole expression would approach infinity. Now they're not going to stay constantly the same difference appart, but ln(x+4) will still be bigger than ln(x) you have something that goes to infinity times something else that goes to infinity. The result will go to infinity.
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