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anonymous
 5 years ago
trapezoidal rule for uneven lengths?
anonymous
 5 years ago
trapezoidal rule for uneven lengths?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how can i take the trapezoidal rule estimation for X's that are not the same in difference? for example: i have x and y values for 0,1, and 3, but not 2. how do i find the y value of 2?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0usually there is an equation to follow.... can you be more specific?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0nvm about the NVM. there is no equation. im just given a table with x and y values.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0then for the trap rule, I would assume the best you can do is add up all the individual areas that they give you right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so youre saying i need to add to trapezoid rules?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0t = 0 1 3 4 7 8 9 L(t) = 120 156 176 126 150 80 0

mathteacher1729
 5 years ago
Best ResponseYou've already chosen the best response.0Oh, so you're not even integrating, you're just trying to find what the function is when you evaluate it at a point which is not given. :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well for now yes, but i need to use the trapezoid sum rule to find the approximate area. thats what my problem says

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and without L(2) i'm left with an expression.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0is there a pattern you can detect?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0nope, its all random Y values

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0if you cant determine L(2), then assume that the interval [1,3] is the base, and use the [L(1)+L(3)]/2 is the height

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the question wants me to start from the first 4 hours, and that starts at time 0 right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the area of a trapezoid is the base times the average height. i would just calculate the area between 1 and 3 and add it into the rest of it

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0your not going to get an exact number any way, the trap areas will see to that :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah .... hope this isnot on the AP test cause ima fail

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i got no idea when the first four hours area, I dont have the problem :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0alright, well thx for helping!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0sure thing, if you wanna post the entire problem, then I might be able to discern it better :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Concert tickets went on sale at noon (t=0) and were sold out within 9 hours. the number of people in line waiting to buy tickets at time t is modeled by a twice differentiable function L for 0<=t <= 9. Use a trapezoial sum rule with 3 sub intervals to estimate the average number of people waiting in line during the first 4 hours that tickets were on sale. t = 0 1 3 4 7 8 9 L(t) = 120 156 176 126 150 80 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry the L(t) is mssed up

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait nevermind is good

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0for starters, take the interval [0,9] and subdivide it into 3 equal intervals [0,3] ;[3,6] ;[6,9] is what it wants you to do right? then you find the area for each trap made according to the value of the "endpoints" of each subinterval..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh wait, so i should take it for the WHOLE thing then divide by 3?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well it says the first 4 hours of sale. not the whole 09 hours

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i was thinking it strts at time 0 and ends at time 3 so that gives me 4 hours since people start to get tickets at time 0

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0..... yeah the first 4 hours. if anything plot all your points on a graph and connect the dots... then determine the heights of your intervals from that

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but the graph could have a decrease at 2 so it would not give me the right y value

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0you cant get the "exact value" regardless, you just have to do the best with what you have.... you cant "create" data that doesnt exist..

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the trap rule is the "best guess" method anyways, so it wont be exact regardless of what you do :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0plot the points. connect the dots, take it where it leads you :)
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