If a particular radio telescope is 100ft in diameter and has a cross section modeled by the equation x^2=167y, how deep is the parabolic dish? What is the location of the focus? can someone help me with this?

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learned a bit more about this stuff today i did....

x^2 = 4ay where a is the distance from the vertex..... and your vertex is at 0,0

167/4 is a so the focus is at..... 0+ 167/4

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