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anonymous
 5 years ago
The point (3, 1/4) is on the graph of
y=f(x), and the slope at each pointy (x,y) on the graph is given by dy/dx=y^2(62x). Find d^2y/dx^2 and evaluate it at the point (3, 1/4).
anonymous
 5 years ago
The point (3, 1/4) is on the graph of y=f(x), and the slope at each pointy (x,y) on the graph is given by dy/dx=y^2(62x). Find d^2y/dx^2 and evaluate it at the point (3, 1/4).

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0since: \[\frac{dy}{dx}=y^2(62x) \rightarrow \frac{dy}{dx}=6y^22y^2x\] \[\frac{d^2y}{dx^2}=12y \frac{dy}{dx}4yx \frac{dy}{dx}2y^2\] \[\rightarrow \frac{d^2y}{dx^2}=(12y4yx)\frac{dy}{dx}2y^2\] now substitute dy/dx in... \[\rightarrow \frac{d^2y}{dx^2}=(12y4yx)(6y^22y^2x)2y^2\] now plug in 3 for x and 1/4 for y.... let me know what you get
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