anonymous
  • anonymous
whats the integral of xe^(4-x) as x approaches infinity?
Mathematics
katieb
  • katieb
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mathteacher1729
  • mathteacher1729
\[\int_{}^{\infty} xe^{4-x}dx\] What is the lower limit? really can't do much without that.
anonymous
  • anonymous
oops, sorry! 4
mathteacher1729
  • mathteacher1729
\[\int_{4}^{\infty} xe^{4-x}dx\] is that the problem?

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anonymous
  • anonymous
yes correct
anonymous
  • anonymous
its not infinity or -infinity, but I cannot find out the answer
anonymous
  • anonymous
Integrate by parts u=x and dv=e^4-x change infinity to t, then evaluate as a limit
anonymous
  • anonymous
(as t goes to infinity)
anonymous
  • anonymous
\[\lim_{4 \rightarrow \infty} -x e^{4-x} -e^{4-x} ?\]
anonymous
  • anonymous
? i have no idea...
anonymous
  • anonymous
x--->infinity
anonymous
  • anonymous
*
anonymous
  • anonymous
Yep, you got the integral right. now sub in your upper and lower limits. Now you should have something with t in it ( y(t) ) Take the limit of this as t goes to infinity

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