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anonymous

  • 5 years ago

x^2 + 3x - 28 = 0

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  1. anonymous
    • 5 years ago
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    please answer this!

  2. anonymous
    • 5 years ago
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    Factor it first.

  3. anonymous
    • 5 years ago
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    my math teacher said not to factor first :/

  4. anonymous
    • 5 years ago
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    Have you learned the quadratic formula?

  5. anonymous
    • 5 years ago
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    yeaa

  6. anonymous
    • 5 years ago
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    \[x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}\] In this case a =1 , b = 3 and c = -28

  7. anonymous
    • 5 years ago
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    like i no how to get this far. x^2 + 3x = 28 and i no that is the first step, then, you are supposed to cut the 3x in half and square it. but im confused because it is a prime and odd number!

  8. anonymous
    • 5 years ago
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    What are you trying to achieve with that equation? Are you trying to find the zeros?

  9. anonymous
    • 5 years ago
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    im trying to find the x and the directions say " solve by completing the square."

  10. anonymous
    • 5 years ago
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    ahhh there you go now we can do something with that.

  11. anonymous
    • 5 years ago
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    Visit this site. Hope it helps. http://www.purplemath.com/modules/sqrquad.htm

  12. anonymous
    • 5 years ago
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    k thanks!

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spraguer (Moderator)
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